Answer:
54
Step-by-step explanation:
Tn = an²+bn
T2 = a2²+2b
2 = 4a +2b
Multiply all through by 2
4 = 8a +4b
4b = 4-8a
T4 = a4² + 4b
20 = 16a +4b
4b = 20-16a
4-8a = 20-16a
16a -8a = 20-4
8a = 16
a = 16/8 = 2
4b = 4-8a = 4-8(2) = 4-16 = -12
b = -12/4 = -3
T6 = a6² + 6b
T6 = 2(36) + 6(-3) = 72 -18 = 54
You need to find points where the line g(x) intercepts the quadratic function f(x) in one and only one point.
Then 3x^2 + 4x -2 = mx - 5
solve 3x^2 + 4x - mx -2 + 5 = 0
3x^2 + (4 - m)x + 3 = 0
In order to there be only one solution (one intersection point) the radicand of the quadratic formula must be 0 =>
b^2 - 4ac = (4 - m)^2 - 4(3)(3) = 0
(4 - m)^2 = 24
4 - m = +/- √(24)
m = 4 +/- √(24) = 4 +/- 2√(6)
Then m, the slope of the line, may be 4 + 2√6 and 4 - 2√6
Answer:
x=3
Step-by-step explanation:
(0,4) is the correct answer.
