Answer:
V candle ≈ 196.9 cm³
Step-by-step explanation:
Volume of cone = ( π·r²·h)/3
V candle = V big cone -V small cone
V candle = [ π·4²·(8+5) - π·2²·5]/3
V candle = ( π·16·13 - π·4·5)/3
V candle = (π·16·13 - π·4·5)/3
V candle = π·(208 - 20)/3
V candle = π·188/3
V candle = 196.8731396
V candle ≈ 196.9 cm³
Area of square base = 324 m²
Length of the square side = √324 = 18
The side of the square is the base of the triangle.
Area of triangle = (1/2)*base* height
135 = (1/2)*18* h
135 = 9h
135/9 = h
15 = h
height = 15 m
To get the height of the Pyramid, the height of the Triangle and half the length of the side of the square form a right angled triangle.
Hypotenus = 15
Half length of square = 18/2 = 9
Height of Pyramid = H
By Pythagoras' Theorem:
15² = H² + 9²
225 =H² + 81
H² + 81 = 225
H² = 225 - 81
H² = 144 Take square root of both sides
H = √144
H = 12
Height = 12 meters.
Option C.
First subtract the 20 from both sides so it is 3x=2x+4 thens ubtract the 2 so x equals 4
Answer:
For X = 11, the expression is equal to 31
Step-by-step explanation:
Hello
For X = 11 you only have to replaced the value into the expression, so:
3(11) + 4(11-8) - 14
33 + 4(3) - 14
33 + 12 - 14
31
Best regards
Hello!
This is a problem about the general solution of a differential equation.
What we can first do here is separate the variables so that we have the same variable for each side (ex. 
with the 
term and 
with the 
term).
Then, we can integrate using the power rule to get rid of the differentiating terms, remember to add the constant of integration, C, to at least one side of the resulting equation.
Then here, we just solve for and we have our general solution.
![y=\sqrt[3]{\frac{1}{2}x^2-x+C}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B2%7Dx%5E2-x%2BC%7D)
We can see that answer choice D has an equivalent equation, so answer choice D is the correct answer.
Hope this helps!
