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3 years ago

6

FIRST CORRECT ANSWER GETS BRAINLIEST!!!

1 answer:

Luba_88 [7]3 years ago

4 0

If two secants are drawn from a point lying outside a circle, then the product of one secant on its outer part is equal to the product of the other secant on its outer part.

DE*CE = AE*BE

DE = CD + CE = 1 + x + 4 = x + 5
AE = AB + BE = 11 + x + 1 = x + 12

(x+5)(x+4)=(x+12)(x+1)
x² + 4x + 5x + 20 = x² + x + 12x + 12
9x + 20 = 13x + 12
20 - 12 = 13x - 9x
8 = 4x
x = 8/4
x = 2

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Answer:

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Step-by-step explanation:

step 1

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we know that

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step 2

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