The answer to this question is Applicant pool. Applicant
pool is a list of persons who have applied in a specific job vacancy. In this
pool, the human resource manager will select applicants who are qualified to
step forward in the application process. The hiring company will then choose
candidates who are qualified to be included in the short list.
Answer:
c. the supply of, and demand for, the stock.
Explanation:
When a company becomes listed on the stock exchange its stock price is determined by the supply of and demand for the stock. If the demand is high then the price of the stock will rise. Company can list its stock on any stock exchange including NASDAQ and NYSE both so NASDAQ is not responsible for setting price of stock and does not determines the stock price.
Jose uses the power of his position to help his employees grow and succeed. Jose is using socialized power.
<h3>
What is Socialised Power? </h3>
- Effective leadership is frequently linked to socialized power demand.
- Instead of just advancing the position and wealth of the leader, these leaders use their influence in ways that are socially beneficial to others and the organization.
- They crave power because it is only with the power that things can be done.
- People are the wellspring of social power. Society derives its force from people's aspirations, vigor, and capacities. Individual power becomes societal power when it is organized and directed through a system.
- Power is necessary to effect change. Changes can be achieved when there is no power, but it will take a lot of fight and effort to make even a small difference.
To learn more about Power refer to:
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Answer:
getting a job is fun cuz u can earn mone
Explanation:
Answer:
Will increase by 10 units
Explanation:
Given the formula for quantity supplied Qxs = 1,000 + PX - 5PY - 2PW
We are told to gauge the effect of increase in input (W) on quantity supplied (Qxs)
So assuming this protein of the equation is constant
1,000 + PX - 5PY= k
That is there is no change in price of X and Y
Qxs= k- P(W)
So it can be seen that an increase in P(W) is a negative change in the equation
Qxs k - ∆10
Resulting in reduction in Qxs by 10
