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ASHA 777 [7]
3 years ago
8

An election ballot asks voters to select two city commissioners from a group of four candidates. In how many ways can this be do

ne?
Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0
Let n = 12
Let r = 6
Replace every n! with 12 and every r! with 6 and then do the math.
nCr = 12!/[(12 - 6)!*6!]
nCr = 479001600/(720)(720)
nCr = 479001600/518400
nCr = 924
There are 924 ways or combinations to select 6 city commissioners from a group of 12 candidates
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Evaluate using properties of arithmetic operations. 12∙121∙13÷(26∙11)∙7÷11
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Answer:

0.1978

Step-by-step explanation:

According to the rule of BODMAS (or FEDMAS), let us do the bracket first.

26·11 = 286

Now, do the multiplication from the left.

12·121·3 = 4356

286·7 = 2002

Now, do the division from the left.

\frac{\frac{4356}{2002} }{11}

=\frac{4356}{2002(11)}

=\frac{396}{2002}

= 0.1978



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