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saveliy_v [14]
3 years ago
8

The diagram shows two campsites on opposite ends of a lake and two triangles formed by intersecting segments from the campsites.

Mathematics
1 answer:
Aleks [24]3 years ago
6 0

Answer:

x=42.3m

Step-by-step explanation:

x/47=82.8/92

92x=3891.6= 42.3m is the distance

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A bag contains: 5 red marbles, 6 blue marbles, 3 green marbles, 4 black marbles, and 2 yellow marbles. A marble will be drawn fr
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green = 3/20

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Find dyldx.<br> 3. y=2x sin(3x)
vredina [299]

Answer:

\large\boxed{\dfrac{dy}{dx}=2\sin(3x)+6\cos(3x)}

Step-by-step explanation:

\dfrac{dy}{dx}=(2x\sin(3x))'\\\\\text{use}\ \bigg(g(x)\cdot f(x)\bigg)'=g'(c)f(x)+g(x)f'(x)\\\\\text{and}\ \bigg(f(g(x))\bigg)'=f'(g(x))\cdot g'(x)\\\\\dfrac{dy}{dx}=(2x)'(\sin(3x))+(2x)(\sin(3x))'\\\\\dfrac{dy}{dx}=2\sin(3x)+(2x)(\cos(3x)\cdot(3x)')\\\\\dfrac{dy}{dx}=2\sin(3x)+2x\cos(3x)\cdot3\\\\\dfrac{dy}{dx}=2\sin(3x)+6\cos(3x)

6 0
3 years ago
A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the
iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

Event\ 1 = \{1,2,3,4,5,6\}

Next, we list out the sample space of F

Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\

6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}

In (1): the sample space of E is:

E = \{1\}

So:

P(E) = \frac{n(E)}{n(Event\ 1)}

P(E) = \frac{1}{6}

In (2): the sample space of F is:

F = \{5,5,5,5\}

So:

P(F) = \frac{n(F)}{n(Event\ 2)}

P(F) =\frac{4}{36}

P(F) =\frac{1}{9}

For E and F to be independent:

P(E\ and\ F) = P(E) * P(F)

Substitute values for P(E) and P(F)

This gives:

P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}

P(E\ and\ F) = \frac{1}{54}

However, the actual value of P(E and F) is 0.

This is so because E = \{1\} and F = \{5,5,5,5\} have 0 common elements:

So:

P(E\ and\ F) = 0

Compare P(E\ and\ F) = \frac{1}{54} and P(E\ and\ F) = 0.

These values are not equal.

Hence: the two events are not independent

6 0
3 years ago
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