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motikmotik
3 years ago
8

a baker has 20 pounds of sugar. He uses 3/4 of the sugar to bake muffins. How many sugar does he have left?

Mathematics
1 answer:
Lostsunrise [7]3 years ago
8 0
- - If a baker has 20 pounds, and looses 3/4 pounds, then we have to take away. Meaning to subtract.


♥ Start with turning 20 into a fraction.

\frac{20}{1} -  \frac{3}{4}

♥ Change this to addition.

\frac{20}{1} + \frac{-3}{4}

♥ Solve for that.

\frac{80}{4} + \frac{-3}{4}

♥ Combine.

\frac{80+-3}{4} = \frac{77}{4} =19.25

She has about 19 (rounded) pounds left.

Decimal exact: 19.25
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The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator
WARRIOR [948]

Answer: 5n = 3d and 3n + 6 = 2d + 4

Given that the numerator and denominator of a fraction are in the ratio of 3 to 5. When the numerator and denominator are both increased by 2, the fraction is equal to \dfrac{2}{3}.  

We are to select the system of equations that could be used to solve the problem.  

Since n denotes the numerator and m denotes the denominator of the given fraction, so we have:

n/d = 3/5

5n = 3d

<h3>and</h3>

(n+2)/(d+2) = 2/3

3(n+2) = 2(d+2)

3n + 6 = 2d + 4

Thus, the required system of equations is,

5n = 3d and 3n + 6 = 2d + 4

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2 years ago
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masya89 [10]

Answer:

Part A = the middle one

Part B = 4 days

Step-by-step explanation:

1,300 / 4 = 325

325 x 4 = 1,300

8 0
3 years ago
Read 2 more answers
Mrs.Gill won certain prize money in a cooking competition.She spent half of the prize money on the clothes,one third on grocery
erma4kov [3.2K]

Answer

Find out the how much prize money did she win.

To proof

Let us assume that the total amount prize money did she win be u.

As given

Mrs.Gill won certain prize money in a cooking competition.

She spent half of the prize money on the clothes

= u -\frac{u}{2}\\ = \frac{u}{2}

one third on grocery

= \frac{u}{2} -\frac{u}{3}

(L.C.M of (2,3) =6 )

= \frac{3u -2u}{6} \\=\frac{u}{6}

gave away the remaining Rs.2000 to an orphanage

2000 = \frac{u}{6}

u =Rs 12000

Rs 12000  prize money did she win.

Hence proved

6 0
3 years ago
A plane with equation xa+yb+zc=1 (a,b,c&gt;0)together with the positive coordinate planes forms a tetrahedron of volume V=16abcF
soldier1979 [14.2K]

Question not well presented.

See correct question presentation below

A plane with equation (x/a) + (y/b) + (z/c) = 1, where a,b,c > 0 together with the positive coordinate planes form a tetrahedron of volume V = (1/6)abc. Find the plane that minimizes V if the plane is constrained to pass through the point P(2,1,1).

Answer:

The plane is x/6 + y/3 + z/3 = 1

Step-by-step explanation:

Given

Equation: (x/a) + (y/b) + (z/c) = 1 where a,b,c > 0

Minimise, V = (1/6) abc subject to

the constraint g = 2/a + 1/b + 1/c = 1

First, we need to expand V

V = (abc)/6

Possible combinations of V taking 2 constraints at a time; we have

(ab)/6, (ac)/6 and (bc)/6

Applying Lagrange Multipliers on the possible combinations of V, we have:

∇V = λ∇g

This gives

<bc/6, ac/6, ab/6> = λ<-2/a², -1/b², -1/c²>

If we equate components on both sides, we get:

(a²)bc/12 = -λ = a(b²)c/6 = ab(c²)/6

Solving for a, b and c;

First, let's equate:

(a²)bc/12 = a(b²)c/6 -- divide through by abc, we have

a/12 = b/6 --- multiply through by 12

12 * a/12 = 12 * b/6

a = 2 * b

a = 2b

Then, let's equate:

(a²)bc/12 = ab(c²)/6 -- divide through by abc, we have

a/12 = c/6 --- multiply through by 12

12 * a/12 = 12 * c/6

a = 2 * c

a = 2c

Lastly, we equate:

a(b²)c/6 = ab(c²)/6 -- divide through by abc, we have

b/6 = c/6 --- multiply through by 6

6 * b/6 = 6 * c/6

b = 2

Writing these three results, we have

a = 2b; a = 2c and b = c

Recalling the constraints;

g = 2/a + 1/b + 1/c = 1

By substituton, as have

2/(2c) + 1/c + 1/c = 1

1/c + 1/c + 1/c = 1

3/c = 1

c * 1 = 3

c = 3

Since a = 2c;

So, a = 2 * 3

a = 6

Similarly, b = c

So, b = 3

So, the plane: (x/a)+(y/b)+(z/c)=1;

By substituton, we have

x/6 + y/3 + z/3 = 1

Hence, the plane

So the plane is x/6 + y/3 + z/3 = 1

5 0
3 years ago
I will give brainliest<br> !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
salantis [7]

Answer:

The horizontal line is the x axis

the vertical line is the y axis

The first number is always the number of the x axis

Example.

(6,9)

6 is in the x axis

9 is in the y axis

find the number 6 in the x axis (the horizontal one) and then go up until the number 9.

7 0
2 years ago
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