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Ede4ka [16]
3 years ago
6

In a certain Algebra 2 class of 24 students, 12 of them play basketball and 7 of them play baseball. There are 4 students who pl

ay both sports. What is the probability that a student chosen randomly from the class plays basketball or baseball?
Mathematics
1 answer:
UNO [17]3 years ago
5 0

Answer:

5/8

Step-by-step explanation:

So, if we add 7 + 12, then it seems that 19 of the 24 students play one of the two sports. But there are 4 students that play both, so we must account for that.

To get the actual number of students that play sports, we must subtract 4 from 19.

19 - 4 = 15

So now we know that 15 out of the 24 students play sports.

We can divide 15 and 24 by 3 to find the simplified fraction.

15 / 3 = 5       24 / 3 = 8

So 5 out of every 8 students plays one of these sports, which means that the probability of picking one of these students is 5/8!

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soldier1979 [14.2K]

Answer:

78.5%

Step-by-step explanation:

The area of the square is equal to diameter squared

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The area of the circle is π × r²

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The percent of the time the point will be in the circle = (Area of the circle) ÷ (Area of the square) × 100

i.e \frac{12.56637061}{16} × 100 = 78.53981631%

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Answer:

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Step-by-step explanation:

Note there is a common difference d between consecutive terms in the sequence, that is

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This indicates the sequence is arithmetic with n th term

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Here a₁ = 40 and d = 100, thus

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a_{32} = 40 + (31 × 100) = 40 + 3100 = 3140

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