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3 years ago

Find the coordinates of the midpoint of the segment given at its endpoints A(5,8) and B(-1, -4)

Mathematics

1 answer:

Studentka2010 [4]3 years ago

7 0

$(x_{m},y_{m} ) = (\frac{X_{A} +X_{B} }{2} ,\frac{Y_{A} + Y_{B} }{2})$

$(x_{m},y_{m} ) = (\frac{5-1}{2} ,\frac{8-4 }{2})$

$(x_{m},y_{m} ) = (\frac{4}{2} ,\frac{4 }{2})$

$(x_{m},y_{m} )$ = (2, 2)

Answer: (2, 2)

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Renee is participating in a fundraiser based on how far she walks around the square field at her elementary school. The field is

RUDIKE [14]

Answer:

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Step-by-step explanation:

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4 years ago

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

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3 years ago

Algebra ,, will mark brainliest!!

Viktor [21]

Answer:

Step-by-step explanation:

(1 1/2,-2)

solve for x and get 1 1/2

solve for y and get -2

7 0

2 years ago

A kitchen measures 3.75 meters by 4.2 meters.

dalvyx [7]

Answer:

a. $A_{(kitchen)}=15.75\ m^2$

b. $A_{(total)}=39.375\ m^2$

Step-by-step explanation:

The formula for calculate the area of a rectangle is:

$A=lw$

Where "l" is the lenght and "w" is the width

a. We know that the kitchen measures 3.75 meters by 4.2 meters; then we can say that:

$l=3.75\ m\\\\w=4.2\ m$

Therefore, substituting these values into the formula, we get that the area of the kitchen is:

$A_{(kitchen)}=(3.75\ m)(4.2\ m)=15.75\ m^2$

b. The area of the living room is one and a half times (1.5 times) that of the kitchen, this is:

$A_{(living)}=(1.5)(15.75\ m)=23.625\ m^2$

Therefore, the total of the living room and the kitchen is:

$A_{(total)}=15.75\ m^2+23.625\ m^2=39.375\ m^2$

3 0

3 years ago

Mrs delles spent 120$ on a bag that was discounted 25%, what was the original price.

luda_lava [24]

Answer:

480

Step-by-step explanation:

7 0

3 years ago

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