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oee [108]
3 years ago
14

Answer 3-4 pleaseeeeee

Mathematics
1 answer:
aivan3 [116]3 years ago
4 0
I think #4 is 4 but I'm not completely sure
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If AC=36 and BC= 18, find AD. Round to the nearest tenth, if necessary.​
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C. 27

Step-by-step explanation:

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Step-by-step explanation:

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Please Help!!! Will give brainliest
qaws [65]

36 cm^2

Step-by-step explanation:

<u>Small</u><u> </u><u>window</u>

Length: 2cm

Width: 2cm

<u>Area</u><u>:</u> 4 cm^2

<u>Big window</u>

Length: 4cm

Width: 3cm

<u>Area</u><u>:</u> 12 cm^2

Total area of the windows:

(Area of 4 small windows + area of 1 big window)

(4 cm^2 x 4 + 12cm^2)

= <u>28 cm^2</u>

<u>Above</u><u> </u><u>window</u><u> </u><u>(</u><u>approx</u><u>.</u><u>)</u>

<u>Rectangle</u>

Length: 3cm

Width: 2cm

<u>Area</u><u>:</u> 6 cm^2

<u>T</u><u>riangle</u>

Base: 1cm

Height: 1cm

<u>Area</u><u>:</u> 2 x 0.5 cm^2 = 1 cm^2

<u>Square</u><u> </u><u>(</u><u>between</u><u> </u><u>the</u><u> </u><u>triangles</u><u>)</u>

Length: 1cm

Width: 1cm

<u>Area</u><u>:</u> 1 cm^2

= 8 cm^2

<u>TOTAL</u><u> </u><u>AREA</u><u> </u><u>OF</u><u> </u><u>ALL</u><u> </u><u>WINDOWS</u>

= AREA OF 4 WINDOWS + AREA OF BIG WINDOW + AREA OF ABOVE WINDOW

= 16 cm^2 + 12 cm^2 + 8 cm^2

<h3>= <u>36 cm^2</u></h3>

<em>I</em><em> </em><em>hope</em><em> </em><em>I</em><em> </em><em>made</em><em> </em><em>the</em><em> </em><em>explanations</em><em> </em><em>clear</em><em> </em><em>enough</em><em> </em><em>to</em><em> </em><em>make</em><em> </em><em>it</em><em> </em><em>easier</em><em> </em><em>for</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>understand</em><em>!</em>

8 0
1 year ago
Plisss help on my assesment
Anon25 [30]

Answer:

The first one is equivalent [the 6x+48 = 2(3x+24)] and the second one is <u>NOT</u> equivalent [the 7x+21 ≠ 2(5x+3)]

Step-by-step explanation:

Just follow distributive property to solve these. You can ignore the first expression in both until you have to compare the answers.

1. 6x+48 and 2(3x+24)

2(3x+24) ---> 2(3x) + 2(24) ---> <u>6x + 48</u>

Bring in the first expression ~ <u>6x+48 and 6x+48 </u>

They are the same, so they are equivalent

2. 7x+21 and 2(5x+3)

2(5x+3) ---> 2(5x) + 2(3) ----> 10x + 6

Bring in the first expression ~ <u>7x+21 and 10x + 6</u>

They are NOT the same, so they are NOT equivalent

6 0
3 years ago
Can you plz help me solove this answer
shtirl [24]
Where is the question?
7 0
3 years ago
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