The probability of selecting two orange marbles with replacement is 36/169.
Data;
- Orange= 6
- Red = 2
- Green = 4
<h3>Probability with replacement</h3>
Since after each draw, the orange marble is replaced.
The total number of marbles in the bag is
6+3+4 = 13
And the number of orange marbles is 6.
For the first selection, the probability of selecting one orange is

After drawn and replaced, the probability of selecting another marble is

And the probability of selecting two orange marbles with replacement is

The probability of selecting two orange marbles with replacement is 36/169.
Learn more on probability here;
brainly.com/question/24756209
Answer:
$849.24
Step-by-step explanation:
The person with the 6% monthly interest would pay 106 a month, while the person with the 20% would pay 130.
Answer:
5/6.
Step-by-step explanation:
Let's list the numbers which fit the condition ' greater than 2 or an odd number':
They are 1, 3, 4, 5, 6. Five numbers, so the required probability is:
5/6.
The cosine of an angle is the x-coordinate of the point where its terminal ray intersects the unit circle. So, we can draw a line at x=-1/2 and see where it intersects the unit circle. That will tell us possible values of θ/2.
We find that vertical line intersects the unit circle at points where the rays make an angle of ±120° with the positive x-axis. If you consider only positive angles, these angles are 120° = 2π/3 radians, or 240° = 4π/3 radians. Since these are values of θ/2, the corresponding values of θ are double these values.
a) The cosine values repeat every 2π, so the general form of the smallest angle will be
... θ = 2(2π/3 + 2kπ) = 4π/3 + 4kπ
b) Similarly, the values repeat for the larger angle every 2π, so the general form of that is
... θ = 2(4π/3 + 2kπ) = 8π/3 + 4kπ
c) Using these expressions with k=0, 1, 2, we get
... θ = {4π/3, 8π/3, 16π/3, 20π/3, 28π/3, 32π/3}