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tiny-mole [99]
3 years ago
14

1. The function of a capacitor in an electric circuit is to A. allow current flow between its plates. B. store electric charges.

C. measure the amount of current in the circuit. D. increase circuit power.
Chemistry
2 answers:
posledela3 years ago
5 0
The correct answer is <span>B. store electric charges. Good luck :)</span>
pogonyaev3 years ago
5 0
B.) Store Electric Charges
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What is the mass of 61.9 L of oxygen gas collected at STP?
Tcecarenko [31]

Answer:

D. 44.2 g O₂

General Formulas and Concepts:
<u>Gas Laws</u>

  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at <em>1 atm, 273 K</em>

<u>Stoichiometry</u>

  • Dimensional Analysis
  • Mole Ratio

Explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

61.9 L O₂ at STP

<u>Step 2: Convert</u>

We know that the oxygen gas is at STP. Therefore, we can set up and solve for how many <em>moles</em> of O₂ is present:

\displaystyle 61.9 \ \text{L} \ \text{O}_2 \bigg( \frac{1 \ \text{mol} \ \text{O}_2}{22.4 \ \text{L} \ \text{O}_2} \bigg) = 2.76339 \ \text{mol} \ \text{O}_2

Recall the Periodic Table (Refer to attachments). Oxygen's atomic mass is roughly 16.00 grams per mole (g/mol). We can use a mole ratio to convert from <em>moles</em> to <em>grams</em>:

\displaystyle 2.76339 \ \text{mol} \ \text{O}_2 \bigg( \frac{16.00 \ \text{g} \ \text{O}_2}{1 \ \text{mol} \ \text{O}_2} \bigg) = 44.2143 \ \text{g} \ \text{O}_2

Now we deal with sig figs. From the original problem, we are given 3 significant figures. Round your answer to the <u>exact</u> same number of sig figs:

\displaystyle 44.2143 \ \text{g} \ \text{O} \approx \boxed{ 44.2 \ \text{g} \ \text{O}_2 }

∴ our answer is letter choice D.

---

Topic: AP Chemistry

Unit: Stoichiometry

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