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Irina-Kira [14]
3 years ago
13

To isolate the variable in the equation -3x - 9 = -27, the first step is to add 9 to both sides. This gives you -3x = -18. What

is the next step to isolate the variable?
 A.+ 18  B.18  C. -3  D.+ 3x
Mathematics
2 answers:
drek231 [11]3 years ago
7 0
Divide both sides of the equation by -3, which gives you x=6.
Vinvika [58]3 years ago
7 0
-3x-9=-27
Add 9 to both side
-3x-9+9=-27+9
-3x=-18
divided -3 to each side
-3x/-3=-18/-3
x=6
Check:
-3x-9=-27
substitute x with 6
-3(6)-9=-27
-18-9=-27
-27=-27. As a result, the next step to isolate the variable is divided -3 to both side. Hope it help!
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3 + 2x = 15
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Ezra can afford to travel 6 miles max.
3 0
3 years ago
If the sum of five consecutive even integers is t, then, in terms of t, what is the greatest integer?
Andre45 [30]
Let x be first integer the we have the sum:-

x + x +2  + x+4 + x+6 + x + 8 = t

5x + 20 = t

5x = t - 20
and x = (t - 20) / 5

so the greatest integer x + 8 = (t - 20) / 5 + 8  =  (t - 20)/5 + 40/5

=  (t + 20) / 5  answer

5 0
3 years ago
7. Lin is saving $300 per year in an account that pays 15% interest per year,
Serga [27]

Answer:

c

Step-by-step explanation:

to much working out but just as a summary section of working out

3*15=45

300+45=$345(1st year)

345+300=645

6.45*15=96.75

645+96.75=$741.75(2nd year)

keep on doing that until you beat 2 in list and use common sense to realise that (d) is too big, and (b, a) is too small so (c) is the correct amount. (this is quicker than actually doing all 20 years)

6 0
3 years ago
Helpp
timama [110]

Answer:

X² + 1 (B)

Step-by-step explanation:

Y = X² + 1

x =2

then X² + 1 = y

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7 0
3 years ago
A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
Mkey [24]

Answer:

(a) Probability that 2 or fewer will withdraw is 0.2061.

(b) Probability that exactly 4 will withdraw is 0.2182.

(c) Probability that more than 3 will withdraw is 0.5886.

(d) The expected number of withdrawals is 4.

Step-by-step explanation:

We are given that a university found that 20% of its students withdraw without completing the introductory statistics course.

Assume that 20 students registered for the course.

The above situation can be represented through binomial distribution;

P(X =r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,......

where, n = number of trials (samples) taken = 20 students

            r = number of success  

            p = probability of success which in our question is probability  

                  that students withdraw without completing the introductory  

                  statistics course, i.e; p = 20%

Let X = <u><em>Number of students withdraw without completing the introductory statistics course</em></u>

So, X ~ Binom(n = 20 , p = 0.20)

(a) Probability that 2 or fewer will withdraw is given by = P(X \leq 2)

P(X \leq 2) =  P(X = 0) + P(X = 1) + P(X = 2)

=  \binom{20}{0} \times 0.20^{0} \times (1-0.20)^{20-0}+ \binom{20}{1} \times 0.20^{1} \times (1-0.20)^{20-1}+ \binom{20}{2} \times 0.20^{2} \times (1-0.20)^{20-2}

=  1 \times1 \times 0.80^{20}+ 20 \times 0.20^{1} \times 0.80^{19}+ 190\times 0.20^{2} \times 0.80^{18}

=  <u>0.2061</u>

(b) Probability that exactly 4 will withdraw is given by = P(X = 4)

                      P(X = 4) =  \binom{20}{4} \times 0.20^{4} \times (1-0.20)^{20-4}

                                 =  4845\times 0.20^{4} \times 0.80^{16}

                                 =  <u>0.2182</u>

(c) Probability that more than 3 will withdraw is given by = P(X > 3)

P(X > 3) =  1 - P(X \leq 3) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

=  1-(\binom{20}{0} \times 0.20^{0} \times (1-0.20)^{20-0}+ \binom{20}{1} \times 0.20^{1} \times (1-0.20)^{20-1}+ \binom{20}{2} \times 0.20^{2} \times (1-0.20)^{20-2}+\binom{20}{3} \times 0.20^{3} \times (1-0.20)^{20-3})

=  1-(1 \times1 \times 0.80^{20}+ 20 \times 0.20^{1} \times 0.80^{19}+ 190\times 0.20^{2} \times 0.80^{18}+1140\times 0.20^{3} \times 0.80^{17})

=  1 - 0.4114 = <u>0.5886</u>

(d) The expected number of withdrawals is given by;

                        E(X)  =  n\times p

                                 =  20 \times 0.20 = 4 withdrawals

3 0
4 years ago
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