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Nikitich [7]
3 years ago
11

Find the values of x and y in these equations. (x + yi) + (4 + 6i) = 7 − 2i (equation A) (x + yi) − (-8 + 11i) = 5 + 9i (equatio

n B)
Mathematics
2 answers:
Arada [10]3 years ago
8 0

Answer:

Step-by-step explanation:

(x+yi)+4+6i=7-2i

x+yi=7-2i-4-6i

x+yi=3-8i

equating real and imaginary parts

x=3,y=-8

B.

x+yi=5+9i+(-8+11i)

x+yi=5+9i-8-11i

x+yi=-3-2i

equating real ,and imaginary parts

x=-3

y=-2

myrzilka [38]3 years ago
3 0

Answer:

1. Equation A:

Solving for x: x=3-yi-8i

Solving for y: y=-3i+xi-8

2. Equation B:

Solving for x: x=-3-yi+20i

Solving for y: y=3i+xi+20

I hope this helped! :)

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Use factoring to find the zeros.<br> x2 - 9x – 36 = 0
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3 years ago
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