Step-by-step explanation:
You can write the equations of motion as
h(t) = -16t² + v₀sin(θ)t
d(t) = v₀cos(θ)t
Solving the second of these for t and substituting into the first equation gives the time of flight as
0 = -16t² + d(t)·tan(θ)
t = √(d(t)·tan(θ)/16)
So, for d(t) = 400 and θ = π/6, this becomes
t = √((400/16)/√3)
t = 5/√(√3) ≈ 3.79918
The ball is in the air about 3.80 seconds.
Answer:
The area of the rectangular field is<u> 2831.25</u> sq. yards.
The perimeter of the rectangular field is<u> 153.1</u> yards
Step-by-step explanation:
Here, the length of the field = 62. 5 yards
The width of the field = 45.3 yards
PERIMETER OF A RECTANGLE = 2 (LENGTH + WIDTH)
⇒ The perimeter of the yard = 2 ( 62.5 + 45.3)
= 2 x (107.8) = 153.1 yards
or the perimeter of the rectangular field is 153.1 yards
Area of a Rectangle = (LENGTH x WIDTH)
⇒ The area of the yard = ( 62.5 x 45.3)
= 2831.25 sq. yards
or the area of the rectangular field is 2831.25 sq. yards.
Answer: 55
The angles that measures 125 and y make a linear pair (equal 180)
So you just do 180-125 to get y
Distance between Brad and bombs falling location we need
- Hypotenuse=H=41m
- Perpendicular=P=40m
Base be B
Apply Pythagorean theorem
- B²=H²-P²
- B²=41²-40²
- B²=9²
- B=9m