Question

Two cars leave the same location at the same time but one car is heading north and the other is heading south. After 3 hours, the cars are 360 miles apart. If the car heading north is traveling 10 miles per hour slower than the car heading south, what are the two speeds of the cars?
SHOW THE EQUATION

Answer 1

$d=vt$
$360=(v_{s})(3)+(v_{n})(3)$
$360=(v_{s})(3)+((v_{s}-10)(3)$
$360=3v_{s}+3v_{s}-30$
$390=6v_{s}$
$v_{s}=\frac{390}{6}=65$
$v_{n}=v_{s}-10=65-10=55$

The south car is traveling at 65mph. The north car is traveling at 55mph. 

Answer 2

3x +3(x-10) = 360

3x +3x-30 =360

6x-30 =360

6x=390

X = 390/6 = 65

65-10 =55

 One car was driving 65 mph

 The other was 55 mph