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stellarik [79]
3 years ago
5

The following list details the numbers of tickets sold for a talent show grade 9:22; grade 10:32; grade 11: 41; and grade 12:30.

What are the
domain and range of this relation?
A domain: (22, 32, 41, 30); range: {9, 10, 11, 12}
B. domain: {9, 22, 10, 32); range: {11, 41, 12, 30}
C. domain: {9, 10, 11, 12); range: (22, 32, 41, 30)
D
domain: {11, 41, 12, 30}; range: {9, 22, 10, 32)
Mathematics
1 answer:
Montano1993 [528]3 years ago
7 0

Answer: C. domain: {9, 10, 11, 12); range: (22, 32, 41, 30)

Step-by-step explanation:

The data set is:

(9, 22)

(10,32)

(11, 41)

(12, 30).

In the usual notation, the number at the left is the input (belons to the domain) and the number in the right is the output (belongs to the range).

Then the domain would be:

{9, 10, 11, 12}

and the range:

{22, 32, 41, 30}

The correct option is C

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Answer:

Part 1:

Yes, the side lengths form a right triangle.

Part 2:

Option d 37.1 cm

Explanation:

We need to use the pythagorean theorem.

In part 1, if the 3 side lengths are a right triangle, then, they must verify:

7.5^2=4.5^2+6^2

By the theorem. Then:

\begin{gathered} 7.5^2=56.25 \\ 4.5^2+6^2=20.25+36=56.25 \end{gathered}

They're equal, then the lengths correspond to a right triangle.

For part 2, we need to use again the theorem. In this case:

\begin{gathered} 12^2+x^2=39^2 \\ x=\sqrt{1521-144} \\ x=\sqrt{1377} \\ x\approx37.1cm \end{gathered}

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1 year ago
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weeeeeb [17]
C(0,3) \\
x_1=0 \\
y_1=3 \\ \\
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\boxed{\overset{\underline{\ \ \ \ }}{CD} = 4\sqrt{2}}
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