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2 years ago

Write an equation in standard form that has a slope of –5/2 and a y-intercept of –2.

Mathematics

1 answer:

vova2212 [387]2 years ago

5 0

Answer:

-5/2+-2

Step-by-step explanation:

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2 years ago

Which of the following is the product of the rational expressions shown below? 7x/x-4•x/x+7

Gre4nikov [31]

<h2>The product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}$ .</h2>

Step-by-step explanation:

We have,

$\dfrac{7x}{x-4}.\dfrac{x}{x+7}$

To find, the product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$ = ?

∴ $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$

= $\dfrac{7x.x}{(x-4)(x+7)}$

= $\dfrac{7x^2}{(x(x+7)-4(x+7)}$

= $\dfrac{7x^2}{x^2+7x-4x-28}$

= $\dfrac{7x^2}{x^2+3x-28}$

Thus, the product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}$ .

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2 years ago

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1 year ago

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Morgarella [4.7K]

$\text{mass of freight train} = 9.98 \times {10}^{6} kg$

$\text{mass of aircraft carrier} = 7.3 \times {10}^{7} \: kg$

$\text{difference of masses of aircraft and train: } \\ \\ 7.3 \times {10}^{7} - 9.98 \times {10}^{6} \\ \\ = 73 \times {10}^{6} - 9.98 \times {10}^{6}$

$= (73 - 9.98 )\times {10}^{6} \\ \\ = 63.02 \times {10}^{6} \\ \\ = 6.302 \times {10}^{6} \: kg \\ \\ \approx 6.3 \times {10}^{6} \: kg$

Approximately, aircraft carrier is 6.3 × 10^6 kg heavier than the freight train.

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2 years ago