Question

Hexagon FUTBOL has coordinates F(3,6), U(5,2), T(2,-3), B(-3,-2), O(-5,1) and L(-2,5), and it is dilated by scale factor of five centered at origin.
What are the coordinates of F'U'T'B'O'L'?

Answer 1

Answer:

$F'(15,\ 30),\ U'(25,\ 10),\ T'(10,\ -15),\ B'(-15,\ -10),\ O'(-25,\ 5),\ L'(-10,\ 25)$

Step-by-step explanation:

We known that ,

When a figure (with coordinate (x,y)) gets dilated by a scale factor k from origin (0,0) , then the coordinate of the new image will become :-

$(x,y)\to(kx,ky)$

Given : Hexagon FUTBOL has coordinates F(3,6), U(5,2), T(2,-3), B(-3,-2), O(-5,1) and L(-2,5), and it is dilated by scale factor of 5 centered at origin.

Then, the coordinates of F'U'T'B'O'L' will be :-

$F(3,6)\toF'(5(3),\ 5(6))=F'(15,\ 30)$

$U(5,2)\toU'(5(5),\ 5(2))=U'(25,\ 10)$

$T(2,-3)\toT'(5(2),\ 5(-3))=T'(10,\ -15)$

$B(-3,-2)\toB'(5(-3),\ 5(-2))=B'(-15,\ -10)$

$O(-5,1) \toO'(5(-5),\ 5(1))=O'(-25,\ 5)$

$L(-2,5) \toL'(5(-2),\ 5(5))=L'(-10,\ 25)$

Hence, the coordinates of F'U'T'B'O'L' will be :-

$F'(15,\ 30),\ U'(25,\ 10),\ T'(10,\ -15),\ B'(-15,\ -10),\ O'(-25,\ 5),\ L'(-10,\ 25)$

Answer 2

It’s B (-3,-2) thats the andwer