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77julia77 [94]
3 years ago
12

If john makes a contribution to a charity fund at school, the average contribution size will increase by 50% reaching $75 per pe

rson. If there were 5 other contributions made before john's, what is the size of his donation?A. $100B. $150C. $200D. $250E. $450
Mathematics
1 answer:
Sonja [21]3 years ago
5 0

Answer:

Z= 75*6 -250=200

So then the correct answer is B. $200.

Step-by-step explanation:

Notation

Let X be the average contribution size before John makes his contribution.

Let Y be the total contribution size before John makes his contribution.

Let Z be John's contribution.

We know that for this case $ 75 represent the original average amount before the contribution with 50% increase so we can set up the following equation in order to find the original average amount

1.5 X = 75

And solvong for X we got:

X = \frac{75}{1.5}= 50

Now we can find the total contribution before the donation with the following proportion:

\frac{50}{1}= \frac{Y}{5}

Y = 250

And then with the formula of average taking in count the 6 values we can find the size of donation Z like this:

\frac{Y+Z}{6}= 75

\frac{250+Z}{6}= 75

Z= 75*6 -250=200

So then the correct answer is B. $200.

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Ok, check your work one way is:

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Now add 4.

4358. So it's correct.

Equation (622x7)+4= 4358

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Step - by - step explanation

<em>3</em><em>/</em><em>1</em><em>1</em><em> </em><em>of</em><em> </em><em>×</em><em> </em><em>=</em><em> </em><em>7</em><em>5</em>

<em>=</em><em>1</em><em>1</em><em>×</em><em>7</em><em>5</em><em>/</em><em>3</em><em>=</em><em>2</em><em>7</em><em>5</em>

<em>there</em><em>fore</em><em> </em><em>8</em><em>=</em><em>8</em><em>/</em><em>1</em><em>1</em><em>×</em><em>2</em><em>7</em><em>5</em><em>=</em><em>2</em><em>0</em><em>0</em>

<em>3</em><em>=</em><em> </em><em>3</em><em>/</em><em>1</em><em>1</em><em>×</em><em>2</em><em>7</em><em>5</em><em>=</em><em> </em><em>7</em><em>5</em><em> </em>

<em>2</em><em>0</em><em>0</em><em>-</em><em>7</em><em>5</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>5</em>

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