Answer and explanation:
Benchmark fractions are fractions that are used as references in measuring other fractions. They are easily estimated and so can be used in measuring more "specific" fractions such as 1/5, 7/9, 3/7, 1/3 etc. If I wanted to measure 1 1/3cm for instance using a calibrated ruler, having centimeter measurements, I would first find 1cm on the ruler and then find half of one centimeter. Seeing that half is bigger than 1/3 but close, I could then estimate 1/3 to be somewhere less than 1/2 but a bit close to it
Answer:
A).Amount = $218250
B). Amount = $88700
Step-by-step explanation:
A) .$5000 in an account at age 23, and withdraw it 42 years
Number of years t= 42 years
Principal P = $5000
Rate r= 9%
Number of times compounded n= 42
A= p(1+r/n)^(nt)
A= 5000(1+0.09/42)^(42*42)
A= 5000(1+0.002143)^(1764)
A= 5000(1.002143)^1764
A= 5000(43.65)
A= 218250
Amount = $218250
B).waits 10 years before making the deposit, so that it stays in the account for only 32 years
Number of years t= 32 years
Principal P = $5000
Rate r= 9%
Number of times compounded n= 32
A= p(1+r/n)^(nt)
A= 5000(1+0.09/32)^(32*32)
A= A= 5000(1+0.0028125)^(1024)
A= 5000(1.0028125)^1024
A= 5000(17.74)
A= 88700
Amount = $88700
Answer:
(4, 6)?
Step-by-step explanation:
Im not sure you didn't give much info
Answer:
We have the magnitude, M, and the angle A.
(The angle is always measured from the +x-axis)
Then we have that:
x = M*cos(A)
y = M*sin(A)
in this case:
M = 9m
A = -80°
x = 9m*cos(-80°) = 1.562
y = 9m*sin(-80) = -8.86m
Now, the component parallel to the x axis is:
x = 9m*cos(-80°) = 1.562 m
And the slope of something parallel to the x-axis is always zero, as this is a constant line.
