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Ludmilka [50]
3 years ago
14

X is directly proportional with Y write an equation that shows the relationship if y equals 6 and x equals one

Mathematics
1 answer:
KiRa [710]3 years ago
7 0
Y=X+5 OR Y=6X CAN BE A EQUATION BUT YOU CAN FORM SOME MORE ALSO
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Find the exact area of the region bounded by two concentric circles with a radii of 10 and 6 inches
bagirrra123 [75]
Hello,

Area=π(10²-6²)=π(100-36)=64π
===========================


6 0
3 years ago
Last month Steve had $125 in his savings account This
ludmilkaskok [199]

20%.

As you can see, he gained 25 dollars within the past month.

There is a simple formula for this.

Increase = New number - original number. Then divide your answer by the original number and multiply by a hundred.

150 - 125 = <u>25</u>

25/125 = <u>0.2</u>

0.2 * 100 = 20%

8 0
4 years ago
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What is the approximate distance between points P and Q? Round your answer to the nearest hundredth.
Debora [2.8K]
The approximate distance between point p and q are 5.1 so the answer is D.
6 0
3 years ago
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Ok, 20 points for this one
arsen [322]

Answer:

<h3>x = 7</h3>

Step-by-step explanation:

2 angles are added to result in = 180°

therefore

180 = 97 - 3x + 69 + 5x

180 = 166 + 2x

2x = 180 - 166

2x = 14

x = 14 ÷ 2

<h3>x = 7 ✅</h3>

The value of x = 7

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#IndonesianPride

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7 0
3 years ago
The point slope form of the equation of the line that passes through (-5-1) and (10.-7) is
Natalka [10]

Answer:

The standard form of the equation for this line can be:

l: 2x + 5y = -15.

Step-by-step explanation:

Start by finding the slope of this line.

For a line that goes through the two points (x_0, y_0) and (x_1, y_1),

\displaystyle \text{Slope} = \frac{y_{1} - y_{0}}{x_{1} - x_{0}}.

For this line,

\displaystyle \text{Slope} = \frac{(-1) - (-7)}{(-5) - 10} = -\frac{2}{5}.

Find the slope-point form of this line's equation using

  • \displaystyle \text{Slope} = -\frac{2}{5}, and
  • The point (-5, -1) (using the point (10, -7) should also work.)

The slope-point form of the equation of a line

  • with slope m and
  • point (x_{0}, y_{0})

should be l:\; y - y_{0} = m(x - x_0).

For this line,

  • \displaystyle m = -\frac{2}{5}, and
  • x_0 = -5, and
  • y_0 = -1.

The equation in slope-point form will be

\displaystyle l:\; y - (-1) = -\frac{2}{5}(x - (-5)).

The standard form of the equation of a line in a cartesian plane is

l: \; ax + by = c

where

a, b, and c are integers. a \ge 0.

Multiply both sides of the slope-point form equation of this line by 5:

l:\; 5 y + 5 = -2x -10.

Add (2x-5) to both sides of the equation:

l: \; 2x + 5y = -15.

Therefore, the equation of this line in standard form is l: \; 2x + 5y = -15.

7 0
3 years ago
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