Answer:
Height of cylinder (h) = (4/3)R
Step-by-step explanation:
Given:
Radius of cylinder (r1) = R
Height of cylinder (h) = H
Radius of sphere (r2) = R
Volume of cylinder = volume of sphere
Find:
Height of cylinder (h) = H = ?
Computation:
Height of cylinder (h) = (4/3)R
Answer:
C.
Step-by-step explanation:
Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.
So, if we're taking f/g, we have:
4x - 3 makes up our denominator, the bottom part of the fraction. So
4x - 3 = 0
4x = 3
x = 3/4
So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.
(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:
If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)
Answer:
The image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:
`The figure of the dilated image is attached below.
Step-by-step explanation:
Given the triangle ΔDLW withe the vertices
As the scale factor 1/2 < 0, thus the image triangle will be smaller than the original triangle.
The rule of dilation is given by
Dilation: (x, y) → (1/2x, 1/2y), centered at (0, 0)
D(0, 2) → D' (1/2x, 1/2y) → D' (1/2(0), 1/2(2)) = D' (0, 1)
L(1, 5) → L'(1/2x, 1/2y) → L'(1/2(1), 1/2(5)) = L' (1/2, 5/2)
W(5, 4) → W'(1/2x, 1/2y) → W'(1/2(5), 1/2(4)) = W' (5/2, 2)
Therefore, the image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:
`The figure of the dilated image is attached below.
