if the permiter is 42 then p=hypotonuse+side+side 42=20+side+side subtract 20 from both sides 22=side+side
a+b=22 subtract b from both sides a=22-b subsitute for a in equation below a+2+b^2=c^2 (22-b)^2+b^2=400 b^2-44x+484+b^2=400 2b^2-44x+484=400 divide both sides by 2 b^2-22x+242=200 subtract 200 from both sides b^2-22x+42=0 factor (b+/-number)(b+/-number) to find the numbers, find which 2 number multiply to 42 and add to get -22 the numbers must be neative since same signs multiplied=positive and negative+negative=negative (b-number)(b-number) facrors of 42=2,3,6,7,14,21 2,21 3,14 6,7 it's hard to find the number, but the numbers are -19.8882 and -2.11181 (b-19.8882)(b-2.11181)=0 if xy=0 then assume that x and y=0
b-19.8882=0 add 19.8882 to both sides b=19.8882
b-2.11181=0 add 2.11181 to both sides b=2.11181
the side legnths are 19.8882 units and 2.11181 units
Sum= addition lets set the problem up like this and let the first number equal A and the second number is B This what we know: 14 = (a ) + 2(B) A - B = 2 We need to find A and B
