21.4666 hope this helps! ❤️
Answer:
30.17feet high
Step-by-step explanation:
Given the following
the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)
angle of elevation = 38°
Required
Height of the flagpole (opposite)
Using the SOH CAH TOA identity
Sin theta = opposite/hypotenuse
Sin 38 = H/49
H = 49sin38
H = 49(0.6157)
H = 30.17feet
Hence the flagpole is 30.17feet high
Answer:y+2.9=11, 2y+1=17.2, 28.4-y=20.3
Step-by-step explanation:
Answer:
3,6,9,12,15
Step-by-step explanation:
First you need to find the surface area of the wall that was painted, and then add the additional area in the hallway that was painted.
The wall that was painted was 9 feet by 10 feet, or 90 square feet. 90 square feet plus the additional 46 square feet in the hallway is 136 square feet, which is the total area that the paint covered.
Therefore the solution is 136 square feet.
