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Lorico [155]
3 years ago
6

How to solve y^2=144/169

Mathematics
1 answer:
jekas [21]3 years ago
7 0
Find the square root of both sides
√y²= √(144/169)

y= √144 / √169
y= 12/13

Final answer: y=12/13
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Subtract (x² + 5x – 6) – (3x^2 – 7x + 1).<br> What is the difference?
Lorico [155]
1. Distribute the Negative Signs
2. Combine like terms
-2x^2 + 12x-7
4 0
3 years ago
What is an equation of the line that passes through the point (-7,-6)(−7,−6) and is parallel to the line x-y=7x−y=7?
kotykmax [81]

Answer:

y = x + 1

Step-by-step explanation:

The gradient of a line can be defined by the equation:

m (gradient) = (y1 – y2 ) ÷ (x1 – x2) ----> "1" and "2" should be in subscript

For (-7,-6) we use x2 and y2 (because this point can be anywhere along a line):

x2 = -7, y2 = -6

Plug these values into the formula above:

m = (y-(-6)) ÷ (x-(-7))

m = (y+6) ÷ (x+7)

At this stage, the equation can't be solved as there are two unknowns. Therefore, the gradient must be found another way. Two lines are parallel if they have the same gradient - in their y=mx+c equations, m will be equal.

x - y=7 is the line alluded to in the question. Rearranging this equation into the line equation format gives:

y = x-7 ---> The gradient (coefficient of x) is 1.

Therefore, the gradient of the other parallel line must also be 1.

This can be substituted into the previous equation to give:

1 = (y+6)÷(x+7)

x+7 = y+6

x+1 = y

Therefore, the answer is y=x+1

5 0
3 years ago
PLEASE HURRY!
Gnoma [55]

Answer:

11

26

44

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Question 28 (1 point)
aniked [119]

Answer:

+ 16

Step-by-step explanation:

x² - 8x = - 10

to complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 4)x + (- 4) = - 10 + (- 4)²

x² - 8x + 16 = - 10 + 16

thus 16 is added to both sides to complete the square

4 0
2 years ago
PLEASE HELP!
erastova [34]

Answer:

15 mph

Step-by-step explanation:

28mi=2  1/3

2   1/3 = 2 hrs 20min

110min

28/110=.254 mi per min

.25*60=15 mi per hrs

8 0
2 years ago
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