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Lorico [155]
3 years ago
6

How to solve y^2=144/169

Mathematics
1 answer:
jekas [21]3 years ago
7 0
Find the square root of both sides
√y²= √(144/169)

y= √144 / √169
y= 12/13

Final answer: y=12/13
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ANYONE up???????????????????????????and can i get help with this
Mashcka [7]

Answer:

here's the solution : -

=》2x - 3y = -29

=》x + 6y = 23

=》x = 23 - 6y

now, plugging the value of x in equation 1, we get : -

=》2x - 3y = -29

=》2 (23 - 6y) - 3y = - 29

=》46 - 12y - 3y = -29

=》-15y = -29 - 46

=》y = -75 ÷ -15

=》y = 5

now, plugging the value of y as 5 in equation 2

=》x + 6y = 23

=》x + (6 × 5.2) = 23

=》x = 23 - 30

=》x = - 7

8 0
3 years ago
Which of the following polynomials is in standard form?
Stels [109]
D. f(x)= x*-9x^o+2x^2-4x+10
7 0
3 years ago
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Roselyn is a college student with two part-time jobs. She works a few hours a day at the college laboratory, which pays her at a
VladimirAG [237]

Answer:

15 hours.

Step-by-step explanation:

We first need to see how much money Rose would earn if she sold the 10 pendents, so we will multiply 4×10.

4×10=40

Now we know, she already has 40 dollars of the 160 dollars she needs.

To find out how much she needs left, we will subtract 40 from 160.

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She needs a total of 120 more dollars from working.

To find out how many hours she needs to work, we will divide 120 by 8.

120÷8=15.

In conclusion, she needs to work for at least15 hours to receive enough money.Please help me by marking this brainliest, and giving a thanks!

8 0
3 years ago
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ollegr [7]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Please help <br> What is x= ?
Nataly [62]

Answer:

x=33^{\circ}

Step-by-step explanation:

First off, your drawing is kinda inaccurate, because the 124^{\circ} looks like a right angle, but as you drew it yourself it doesn't matter too much.

We know that the sum of the angles of a triangle will always equal 180^{\circ}, so we have that 23+124+x=180.

Combining like terms on the left side gives 147+x=180.

Subtracting 147 from both sides gives x=33.

So, \boxed{x=33^{\circ}} and we're done!

5 0
2 years ago
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