Answer:
import java.util.Scanner;
public class Solution {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter your value");
int value = scan.nextInt();
greaterThanFive(value);
}
public static void greaterThanFive(int userInput){
System.out.println(userInput > 5);
}
}
Explanation:
The first line import the Scanner which is use to enable to accept user input.
The class is defined as Solution in the next line. The main method is declared in the next line which signify the beginning of the program.
Then, a scanner object is declared called scan in the next line. Then a prompt is display to the user to input a value. The user input is stored in the variable value. The value is then passed to the method greaterThanFive.
The method greaterThanFive is declared and have just one parameter, the userInput. Inside the method, we output if the userInput is greater than 5 using the logical operator (>).
Answer:
rules about the best way to communicate
Explanation
rules about being proper and polite
Answer:
<h3>
<em><u>C</u></em><em><u>.</u></em><em><u> </u></em><em><u> </u></em><em><u>City</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>state</u></em><em><u> </u></em><em><u>where</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>was</u></em><em><u> </u></em><em><u>published</u></em></h3>
Explanation:
<h3>#CarryOnLearning</h3>
Answer:
if (arr[i] > max) -> max3 = max2, max2 = max , max = arr[i]. else if (arr[i] > max2) -> max3 = max2, max2 = arr[i]. else if (arr[i] > max3) -> max3 = arr[i]. At the end of the loop, we will print all three values.
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3