Answer:
"The type of the software which a user wants to use" is a consideration point for the amount of ram while purchasing the computer system.
Explanation:
- The Ram is primary memory, which is used when the system is in on mode. When there is less amount of Ram, then the user of the computers can not able to run multiple programs or runs that type of program which consumes more memory.
- And if there is a high amount of RAM memory, then the user can run multiple programs at the same time or can run that program which takes more memory.
- So when any user wants to decide about the Ram, then he can by deciding the type of software, which he wants to use. How much that software can use the memory.
Answer:
a)
#include <iostream>
using namespace std;
int main() {
bool a,b,c;
cin>>a>>b;
if(a^b)//X-OR operator in C++.
c=true;
else
c=false;
cout<<c;
return 0;
}
b)
#include <iostream>
using namespace std;
int main() {
bool a,b,c,d;
cin>>a>>b>>c;
if((a^b)^c)//X-OR operator in C++.
d=true;
else
d=false;
cout<<d;
return 0;
}
Explanation:
The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.
In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.
Answer:
The answer is "For the stop and wait the value of S and R is equal to 1".
Explanation:
- As we know that, the SR protocol is also known as the automatic repeat request (ARQ), this process allows the sender to sends a series of frames with window size, without waiting for the particular ACK of the recipient including with Go-Back-N ARQ.
- This process is mainly used in the data link layer, which uses the sliding window method for the reliable provisioning of data frames, that's why for the SR protocol the value of S =R and S> 1.
"start", "control panel", "administrative tools", "computer management" thats it
