Answer:
The answer is "delete temp;".
Explanation:
- In the given code a class "doublyLinkedList" is defined that contains a method that is destroy(). This code uses a scope resolution operator to define the method outside the class.
- To access this method write return type of function then class name:: (use scope resolution operator) and function name.
- In this function, nodeType temp is a pointer variable that is used to delete the node.
- In method definition, a loop is declared that check value that is first not equal to nullptr. which means the first node is not equal to null. In this loop, a temp variable holds the first variable value and the first variable value is holding another variable value and then use the "delete temp" statement to delete a node in the list.
- Outside a loop, the last variable holds nullptr variable value and the count variable assigns a value that is 0.
The answer is either B) or D) because I remember learning this and the keyword I remember is analogue
Hope this helps —- XoXo
Answer: Larz7, Dracofli0, butterbro171,OVOclan1011, ect.
Explanation:
Answer:
The correct answer to the following question will be "Θ(n2)
". The further explanation is given below.
Explanation:
If we're to show all the objects that exist from either the first as well as the second vector, though not all of them, so we'll have to cycle around the first vector, so we'll have to match all the objects with the second one.
So,
This one takes:
=
And then the same manner compared again first with the second one, this takes.
=
Therefore the total complexity,
= Θ(n2)
Answer:
方法/步骤
右键单击以选择此计算机,然后有一个菜单来选择属性。
选择后,打开属性面板以找到我们的高级系统设置。
打开后,我们在系统设置下找到高级设置。
打开后,我们看到下面有一个环境变量选项。
打开后,我们在右下角看到一个删除选项。
单击删除到,在右下角后单击删除,然后单击确定的选项。 ...
本文未经授权摘自百度经验