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Romashka-Z-Leto [24]
4 years ago
14

What is the slope pf 10x 12y=60?

Mathematics
1 answer:
bearhunter [10]4 years ago
6 0
10*12y=60
10*12=120
120y=60 
60/120 = .5
y=.5
slope is .5 or 1/2

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The area of a square is 289 centimeters squared. What is the perimeter?​
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Write an expression for the operation described below.<br> c minus b
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2-3 is an expression. Right?

Step-by-step explanation:If so, that was easy.


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When 2 5/8 is written as an improper fraction in lowest terms, what is the numerator of the fraction?
Mama L [17]

Option E

The numerator of fraction is 21

<h3><u>Solution:</u></h3>

2\frac{5}{8} is to be written as improper fraction in lowest terms

To find: numerator of fraction

An improper fraction is a fraction in which the numerator (top number) is greater than or equal to the denominator (bottom number).

<em><u>To convert a mixed fraction to an improper fraction, follow these steps:</u></em>

  • Multiply the whole number part by the fraction's denominator.
  • Add that to the numerator.
  • Then write the result on top of the denominator.

2\frac{5}{8} = \frac{8 \times 2 + 5}{8} = \frac{16 + 5}{8} = \frac{21}{8}

Thus the numerator of fraction is 21. Option E is correct

8 0
4 years ago
whats the equation for the perpendicular bisector of the line segment whose endpoints are (-5,3) and (3,7)?
riadik2000 [5.3K]

Answer:

The equation of perpendicular bisector of the line segment passing through  (-5,3) and (3,7) is: y = -2x+3

Step-by-step explanation:

Given points are:

(-5,3) and (3,7)

The perpendicular bisector of line segment formed by given points will pass through the mid-point of the line segment.

First of all we have to find the slope and mid-point of given line

Here

(x1,y1) = (-5,3)

(x2,y2) = (3,7)

The slope will be:

m = \frac{y_2-y_1}{x_2-x_1}\\m = \frac{7-3}{3+5}\\m = \frac{4}{8}\\m = \frac{1}{2}

The mid-point will be:

(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\ = (\frac{-5+3}{2},\frac{3+7}{2})\\= (\frac{-2}{2},\frac{10}{2})\\=(-1,5)

Let m1 be the slope of the perpendicular bisector

Then using, "Product of slopes of perpendicular lines is -1"

m.m_1 = -1\\\frac{1}{2}.m_1 = -1\\m_1 = -1*2\\m_1 = -2

We have to find the equation of a line with slope -2 and passing through (-1,5)

The slope-intercept form is given by:

y = mx+b\\y = -2x+b

Putting the point (-1,5) in the equation

5 = -2(-1)+b\\5 = 2+b\\b = 5-2\\b = 3

The final equation is:

y = -2x+3

Hence,

The equation of perpendicular bisector of the line segment passing through  (-5,3) and (3,7) is: y = -2x+3

4 0
3 years ago
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