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bija089 [108]
3 years ago
12

Stretch Your Thinking Ann arranges her marbles in groups, with 8 marbles in each group. She writes the fraction 5/8 to show the

fraction of marbles in each group that is red. What equivalent fraction names the fraction of marbles in 6 groups that are Red? Explain.

Mathematics
1 answer:
amid [387]3 years ago
7 0
Create an equivalent fraction with a factor of 6. 6 groups in literal terms means to multiply by 6. Please see the attached picture for the work. The answer is 30 red marbles.

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What is the sum of the geometric sequence 1,3,9... if there were 11 terms?
Delicious77 [7]

Answer:

88,573

Step-by-step explanation:

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3 years ago
What is my number my number is a perfect square the only prime number in it prime factorization is 2 my number is a factor of 32
WITCHER [35]
Nmkndj;n;bnjngfndjknh;rtnh 216g6n
543646245mh.nrkjhgjn.kjgnrjkbuhjtbyultkngu;njktnj totm,my fotrtunanhioubgrviuebglryrhntonm my forytunabjvfdjkfvghyulbfwqlcbherovbegiunj gtjgbasyhj.bsf.fjkbgilhbjbhfljbvhuj
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3 years ago
4(c-3)=8 plz plz plz plz
masha68 [24]
Are you looking for c? if so c=5
6 0
3 years ago
Read 2 more answers
I need help on this,
kondor19780726 [428]

Answer:

C

Step-by-step explanation:

You can eliminate answer A because when X=1, Y must equal 33.75 not 33.

You can eliminate answer B because when X=0, Y must equal 0 not 1.

You can eliminate answer D because this answer has the X and Y coordinates reversed.  When X=1, Y= 33.75.  When X=4, Y=135, etc.

8 0
3 years ago
If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95​% confident that the d
katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}

n = 118.6

Rounding up

We need a sample size of least 119

6 0
3 years ago
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