All categories

3 years ago

Which number is greater 65% or 0.56

Mathematics

2 answers:

coldgirl [10]3 years ago

8 0

65% is bigger than 0.56 which would be 56%

anyanavicka [17]3 years ago

5 0

65% is greater than 0.56 because 65% in decimal from is 0.65 or if u wanted 0.56 in percentage form its 56%.

You might be interested in

If n is at least 7, which inequality best represents the values of n?

Wittaler [7]

Answer:

The answer to your question is C.n ≥ 7

Step-by-step explanation:

I hope this helps and have a good day!

3 0

1 year ago

Which statement is true?

marshall27 [118]

Answer:

B, the second answer choice

Step-by-step explanation:

Hope this helped! Please mark me as brainliest if you can!

4 0

3 years ago

Can u help with this one u know who u are

tatiyna

It's the one on the top righr, -2/9 w + 2/15.

8 0

3 years ago

Read 2 more answers

Someone please help!

USPshnik [31]

Here are the log properties you need:
$log(ab) = log(a) +log(b) \\ \\ log(\frac{a}{b}) = log(a) - log(b) \\ \\ log(a^n) = n log(a)$

6 0

3 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

3 years ago