Answer: 24.52%
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Work Shown:
Convert the time 7:45, which represents 7 min 45 sec, to seconds only
7:45 = (7 min) + (45 sec)
7:45 = (7*60 sec) + (45 sec)
7:45 = (420 sec) + (45 sec)
7:45 = (420+45) sec
7:45 = 465 sec
Do the same for 5:51
5:51 = (5 min) + (51 sec)
5:51 = (5*60 sec) + (51 sec)
5:51 = (300 sec) + (51 sec)
5:51 = (300+51) sec
5:51 = 351 sec
So the initial time is 465 seconds and it drops to 351 seconds
Subtract the values to find the amount dropped: 465-351 = 114
Divide that difference over the initial time: 114/465 = 0.24516
Move the decimal over 2 spots to the right to convert to a percentage: 0.24516 --> 24.516%
Then round to the nearest hundredth of a percent (2 decimal places) to go from 24.516% to 24.52% which is our final answer
So the reduction is roughly 24.52%
This means if you took 24.52% of the initial time and subtracted it off, then you'd get to about 351 seconds.
Answer:Set \displaystyle f\left(x\right)=0f(x)=0.
Step-by-step explanation:
Set \displaystyle f\left(x\right)=0f(x)=0.
If the polynomial function is not given in factored form:
Factor out any common monomial factors.
Factor any factorable binomials or trinomials.
Set each factor equal to zero and solve to find the \displaystyle x\text{-}x- intercepts.
2+2=4 2 X 2 = 4 2 X 3 = 6
recalling that d = rt, distance = rate * time.
we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?
so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.
then Wanda kicks in, rolling like a lightning at 16mph.
let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.
the distance both have travelled is the same "d" miles, reason why they "meet", same distance.
![\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bmiles%7D%7Bdistance%7D%26%5Cstackrel%7Bmph%7D%7Brate%7D%26%5Cstackrel%7Bhours%7D%7Btime%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20Hector%26d%2612%26t%2B%5Cfrac%7B3%7D%7B2%7D%5C%5C%5B1em%5D%20Wanda%26d%2616%26t%20%5Cend%7Barray%7D%5Cqquad%20%5Cimplies%20%5Cbegin%7Bcases%7D%20%5Cboxed%7Bd%7D%3D%2812%29%5Cleft%28%20t%2B%5Cfrac%7B3%7D%7B2%7D%20%5Cright%29%5C%5C%5B1em%5D%20d%3D%2816%29%28t%29%20%5Cend%7Bcases%7D)
