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2 years ago

PLS HELPLO Find the change in x for ordered pairs (6,-3) and (5, 1) *

Mathematics

1 answer:

Ghella [55]2 years ago

5 0

Answer:

The change in x = Δx = -1

Step-by-step explanation:

Given the ordered pairs

(6, -3)

(5, 1)

Here,

x₁ = 6

x₂ = 5

y₁ = -3

y₂ = 1

Change in x can be calculated by subtracting the value of x₁ = 6 from x₂ = 5.

Change in x = Δx = x₂ - x₁ = 5 - 6 = -1

Thus, the change in x = Δx = -1

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Bowling alley A charges to rent shoes and per game. Bowling alley B charges to re shoes and per game. a. For what numbers of gam

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The computation shows that the price of each game is $2.5 and the price of shoe rental will be $3.

<h3>How to illustrate the information?</h3>

Fron the information given, the equation will be:

s + 4g = 13

s + 8g = 23

4g = 10

g = 2.5

Therefore, the price of each game is $2.5

The price of shoe rental will be:

s + 4g = 13

s + 4(2.50) = 13

s = 13 - 10.

s = 3

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Recent census data indicated that 14.2% of adults between the ages of 25 and 34 live with their parents. A random sample of 125

kicyunya [14]

Answer:

The probability is $P(14 < X < 20 ) = 0.5354$

Step-by-step explanation:

From the question we are told that

The proportion that live with their parents is $\r p = 0.142$

The sample size is n = 125

Given that there are two possible outcomes and that this outcomes are independent of each other then we can say the Recent census data follows a Binomial distribution

i.e

$X \ \~ \ B( \mu , \sigma )$

Now the mean is evaluated as

$\mu = n * \r p$

$\mu = 125 * 0.142$

$\mu = 17.75$

Generally the proportion that are not staying with parents is

$\r q = 1 - \r p$

= > $\r q = 0.858$

The standard deviation is mathematically evaluated as

$\sigma = \sqrt{n * \r p * \r q }$

$\sigma = \sqrt{ 125 * 0.142 * 0.858 }$

$\sigma = 3.90$

Given the n is large then we can use normal approximation to evaluate the probability as follows

$P(14 < X < 20 ) = P( \frac{ 14 - 17.75}{3.90}$

Now applying continuity correction

$P(14 < X < 20 ) = P( \frac{ 13.5 - 17.75}{3.90} < \frac{ X - \mu }{\sigma } < \frac{ 19.5 - 17.75}{3.90} )$

Generally

$\frac{ X - \mu }{\sigma } = Z ( The \ standardized \ value \ of X )$

$P(14 < X < 20 ) = P( \frac{ 13.5 - 17.75}{3.90} < Z< \frac{ 19.5 - 17.75}{3.90} )$

$P(14 < X < 20 ) = P( -1.0897 < Z< 0.449 } )$

$P(14 < X < 20 ) = P( Z< 0.449 ) - P(Z < -1.0897)$

So for the z - table

$P( Z< 0.449 ) = 0.67328$

$P(Z < -1.0897) = 0.13792$

$P(14 < X < 20 ) = 0.67328 - 0.13792$

$P(14 < X < 20 ) = 0.5354$

6 0

3 years ago