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3 years ago

When you select Insert and click on a shape the mouse pointer turns into a/an

Computers and Technology

2 answers:

o-na [289]3 years ago

6 0

The answer to this is C I-beam

S_A_V [24]3 years ago

6 0

Depending on the situation, the shape of the pointer may be an arrow, an I-beam, a hand, or an hourglass (Figure 5)

⇒The arrow pointer is displayed when the pointer is on a command or other selectable item. Click the pointer on the command to select it. Hover, don’t click, over any Ribbon command or icon to display a pop-up description.

⇒The I-beam pointer is displayed within a document. Move the I-beam with the mouse and then click to move the insertion point to that location.

⇒The hand pointer appears when pointing to a hyperlink, like that found in a help window displayed by the Tell Me box. When you click a link a browser window opens.

⇒The hourglass pointer is displayed to indicate that Word is working on an action.

The answer is C. I-beam

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Use the variables k, d, and s so that they can read three different values from standard input--an integer, a double, and a stri

Nat2105 [25]

Answer:

The c++ program to implement the given scenario is shown below.

#include <iostream>

using namespace std;

int main() {

// variables declared as mentioned

int k;

double d;

string s;

cout << " Enter an integer value, a double value, a string value in the mentioned order " << endl;

cin >> k >> d >> s;

// variables printed in reverse order

cout << " Reverse order " << endl;

cout << s << " " << d << " " << k << endl;

// variables printed in original order

cout << " Original order " << endl;

cout << k << " " << d << " " << s << endl;

return 0;

}

OUTPUT

Enter an integer value, a double value, a string value in the mentioned order

12 45.67 brainly

Reverse order

brainly 45.67 12

Original order

12 45.67 brainly

Explanation:

1. All the variables are declared as mentioned in the question.

int k;

double d;

string s;

2. The user is prompted to enter values for integer, double and string variables respectively. The input is accepted in the order mentioned above.

cin >> k >> d >> s;

3. The input is accepted in a single line since this is mentioned in the scenario that variables should be printed in the order in which they are read.

4. These variables are displayed to the standard output in reverse order – string, double, integer. The variables are displayed with exactly one space in between them.

cout << s << " " << d << " " << k << endl;

5. Then, variables are displayed in the original order – integer, double, string. The variables are displayed with exactly one space in between them.

cout << k << " " << d << " " << s << endl;

7 0

2 years ago

More registers appear to be a good thing, in terms of reducing the total number of memory accesses a program might require. Give

gulaghasi [49]

Answer:

Following is given the answer step by step:

Explanation:

First of all we will write a program using MARIE that will support the statement: Sum = (A + B) - (C + D). All the necessary comments are given in front of each statement:

Load A # variable A will be loaded

Add B # B will be added to A

Store Temp1 # A + B will be stored in Temp1

Load C # C will be loaded in memory

Add D # D will be added to C

Store Temp2 # C + D will ge stored in Temp2

Load Temp1 # Temp1 will be loaded in the memory

Subt Temp2 # Temp2(A + B) get subtracted from Temp1(A - B)

Store Sum # (A + B) - (C + D) will get stored in Sum.

We can see from above program that memory is accessed 9 times. While if C + D get executed first than memory accesses will be reduced to 7.

Above same program could be written using an architecture of 4 registers:

The program is as follows:

Load R1 , A #A will be loaded into R1

Load R2 , B # B will be loaded into R2

Add R1 , R2 # R2 gets added to R1 and the result is stored in R1 (A + B)

Load R3 , C # C loaded into R3

Load R4 , D # D loaded into R4

Add R3 , R4 # Value in R4 gets added into R3 and R3 becomes (C + D)

#no memory accesses required for this operation

Subt R1 , R4 #R4 (C + D) gets subtracted from R1 (A + B)

#no memory accesses required for this operation

Store Sum # The recent value will be stored into Sum

Here memory is accessed 5 times in total.

8 0

3 years ago

How to become a web developer ?

statuscvo [17]

Explanation:

1.By Learning web development Fundamentals.

2.Choose a development specialization.

5 0

3 years ago

I need answer poooo<br>

Fiesta28 [93]

Answer:

what is this?Are yhere any options for this question ❓

7 0

2 years ago

Illustrate that the system is in a safe state by demonstrating an order in which the threads may complete.If a request from thre

Kamila [148]

Answer:

a. safe sequence is T2 , T3, T0, T1, T4.

b. As request(T4) = Available, so the request can be granted immediately

c. As request(T2) < Available, so the request can be granted immediately

d. As request(T3) < Available, so the request can be granted immediately.

Explanation:

It will require matrix

[i, j] = Max [i, j] – Allocation [i, j]

A B C D

T0 3 3 3 2

T1 2 1 3 0

T2 0 1 2 0

T3 2 2 2 2

T4 3 4 5 4

Available = (2 2 2 4)

1. Need(T2) < Available so, T2 can take all resources

Available = (2 2 2 4) + (2 4 1 3) (Allocation of T2) = (4 6 3 7)

2. Need(T3)<Available so, T3 will go next

Available = (4 6 3 7) + (4 1 1 0) = (8 7 4 7)

Like wise next T0, T1, T4 will get resources.

So safe sequence is T2 , T3, T0, T1, T4.

(Note, there may be more than one safe sequence).

Solution b.

Request from T4 is (2 2 2 4) and Available is (2 2 2 4)

As request(T4) = Available, so the request can be granted immediately.

Solution c.

Request from T2 is (0 1 1 0) and Available is (2 2 2 4)

As request(T2) < Available, so the request can be granted immediately.

Solution d.

Request from T3 is (2 2 1 2) and Available is (2 2 2 4)

As request(T3) < Available, so the request can be granted immediately.

5 0

3 years ago