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zzz [600]
3 years ago
12

What is the velocity of a 0.100kg car with a momentum of 5 kgm/s?

Computers and Technology
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer:

v = 50 m/s

Explanation:

p = mv

5 = 0.1v

v = 50

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Type of file containing instructions that tell your computer how to perform ___
julsineya [31]

Answer:

A)File

B)Native

C)Extension

D)File size

Explanation:

6 0
3 years ago
To support an internet client, you must have six elements. the first three -- a computer, an operating system and tcp/ip -- are
UkoKoshka [18]
<span>Client software, Internet connection and Internet address</span>
6 0
3 years ago
Which of the following types of operating systems does Windows® belong to?
Masja [62]

Answer:

C) Single-user, multi-tasking operating systems

5 0
3 years ago
g Write a program that prompts the user for an integer n between 1 and 100. If the number is outside the range, it prints an err
grin007 [14]

Answer:

The cpp program is given below.

#include<iostream>

#include<iomanip>

using namespace std;

int main() {

   

   // variables declared

   int n;

   int sum=0;

   float avg;

   

   do

   {

       // user input taken for number    

       cout<< "Enter a number between 1 and 100 (inclusive): ";

       cin>>n;

       

       if(n<1 || n>100)

           cout<<" Number is out of range. Enter valid number."<<endl;

       

   }while(n<1 || n>100);

   

   cout<<" "<<endl;

   

   // printing even numbers between num and 50  

   for(int num=1; num<=n; num++)

   {

       sum = sum + num;

   }

   

   avg = sum/n;

   

   // displaying sum and average

   cout<<"Sum of numbers between 1 and "<<n<<" is "<<sum<<endl;

   cout<<"Average of numbers between 1 and "<<n<<" is ";

   printf("%.2f", avg);

   

       return 0;

}

OUTPUT

Enter a number between 1 and 100 (inclusive): 123

Number is out of range. Enter valid number.

Enter a number between 1 and 100 (inclusive): 56

 

Sum of numbers between 1 and 56 is 1596

Average of numbers between 1 and 56 is 28.00

Explanation:

The program is explained below.

1. Two integer variables are declared to hold the number, n, and to hold the sum of numbers from 1 to n, sum. The variable sum is initialized to 0.

2. One float variable, avg, is declared to hold average of numbers from 1 to n.

3. User input is taken for n inside do-while loop. The loop executes till user enters value between 1 and 100. Otherwise, error message is printed.

4. The for loop executes over variable num, which runs from 1 to user-entered value of n.

5. Inside for loop, all the values of num are added to sum.

sum = sum + num;

6. Outside for loop, average is computed and stored in avg.

avg = sum/n;

7. The average is printed with two numbers after decimal using the following code.

printf("%.2f", avg);

8. The program ends with return statement.

9. All the code is written inside main() and no classes are involved.

3 0
3 years ago
Return the "centered" average of an array of ints, which we'll say is the mean average of the values, except ignoring the larges
denpristay [2]

Answer:

The code to this question can be defined as follows:

public double centeredAverage(ArrayList<Integer> nums) //defining a method centeredAverage that accepts an array nums

{

   if ((nums == null) || (nums.size() < 3))//define if block for check simple case value

   {

       return 0.0;//return float value

   }

   double sum = 0; //defining a double variable sum

   int smallest = nums.get(0);//defining integer variable and assign value

   int largest = nums.get(0);//defining integer variable and assign value

   for (int i = 0; i < nums.size(); i++) //defining for loop for stor ith value

   {

       int value = nums.get(i);//defining integer value variable to hold nums value

       sum = sum + value;//use sum variable for add value

       if (value < smallest)//defining if block to check value less then smallest

           smallest = value;//hold value in smallest variable  

       else if (value > largest)//defining else if block that checks value greater them largest value

           largest = value; //hold value in largest variable

   }

   sum = sum - largest - smallest;  // use sum to decrease the sum largest & smallest value

   return (sum / (nums.size() - 2)); //use return keyword for return average value

}

Explanation:

In the question, data is missing, that's why the full question is defined in the attached file please find it.

In the given code a method "centeredAverage" is used that accepts an array in its parameter and inside the method, if block is used that checks the cash value if it is true, it will return a float value.

In the next step, two integers and one double variable is defined, that use the conditional statement for check hold value in its variable and at the last use return keyword for return average value.

3 0
4 years ago
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