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3 years ago

Given a polynomial p(x) and a value p(a) = 0, determine what is true about the polynomial

Mathematics

1 answer:

AnnyKZ [126]3 years ago

5 0

Your,,,,,, g....a.....y...as....f

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Heisnsbdjjhejejebehwjsjd

irakobra [83]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

72/63 in simplest form

Viktor [21]

$\frac{72}{63}$
Divide both the numerator and denominator by 9 to get;
$\frac{8}{7}$
Convert the improper fraction to a mixed number;
$\frac{8}{7} =1 \frac{1}{7}$

3 0

3 years ago

A chef's specialty calls for one- fiftieth of an ounce of a spice per serving. The chef has a digital scale that shows the wei

Anna35 [415]

Answer:

The scale reading that the chef need to see for this spice when preparing the specialty for 43 people is 0.86.

Step-by-step explanation:

In order to find the answer, you need to multiply the amount that the chef uses per serving for the number of servings. The statement indicates that the chef uses one- fiftieth of an ounce of a spice per serving and this is represented as 1/50 and you have to multiply this for 43 that is the number of people.

You can find 1/50 as a decimal dividing 1 by 50:

1/50=0.02

Now, you can multiply this value for 43:

0.02=43=0.86

According to this, the answer is that the scale reading that the chef need to see for this spice when preparing the specialty for 43 people is 0.86.

3 0

2 years ago

PLS HELPPPP GRADES DUE!

Doss [256]

Answer:

Step-by-step explanation:

Starting with ΔABC, draw the dilation image of the triangle with a center at the origin and a scale factor of two. Notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). Dilations involve multiplication! Dilation with scale factor 2, multiply by 2

4 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28

Nataliya [291]

Assuming you mean

$5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t$

This ODE is linear in $y$ , and you can already contract the left hand side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t$

Integrating both sides with respect to $t$ yields

$5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt$
$5y\sin t=\dfrac13\sin^3t+C$
$y=\dfrac1{15}\sin^2t+C\csc t$

Given that $y\left(\dfrac\pi2\right)=9$ , we have

$9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2$
$9=\dfrac1{15}+C$
$C=\dfrac{134}{15}$

so that the particular solution over the interval is

$y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t$

6 0

3 years ago