Ohm's law equation used to solve this problem is; V = IR where V - voltage I - current passing R - resistance voltage is the potential difference between 2 points and current passing through these 2 points is proportional to the potential difference, in other words voltage. V∞I Resistance is the constant in the equation the current required to pass through is 0.05 A (amperes) the battery voltage is 3.0 V (volts) substituting these values 3 V = 0.05 A * R R = 3/0.05 R = 60 Ω (ohms)
