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Vlad1618 [11]
3 years ago
11

Can anyone give me some questions for algebra 1

Mathematics
1 answer:
iris [78.8K]3 years ago
6 0
If you're asking for a question then
5w(3+9x)=x-2w
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URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.
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In the second quadrant, both cos and tan are negative while only sin is positive.

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\large{ {tan}^{2}  \theta =  {( -  \frac{3}{2}) }^{2}  - 1} \\   \large{ {tan}^{2}  \theta =   \frac{9}{4}  - 1} \\   \large{ {tan}^{2}  \theta = \frac{9}{4}   -  \frac{4}{4} \longrightarrow  \frac{5}{4}  } \\  \large{tan \theta =  \frac{ \sqrt{5} }{ \sqrt{4} } } \\  \large \boxed{tan \theta =  \frac{ \sqrt{5} }{2} }

Since tan is negative in the second quadrant. Hence,

\large{ \cancel{ tan \theta  =  \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta =  -  \frac{ \sqrt{5} }{2} }}

Answer

  • tan = -√5/2
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