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3 years ago

Please help me !!!!!

Mathematics

2 answers:

notka56 [123]3 years ago

8 0

Answer:

the answer is 12

Step-by-step explanation:

MakcuM [25]3 years ago

3 0

Answer:

Second option

$x =9$

Step-by-step explanation:

To solve this problem we use the secant theorem.

If two secant lines intersect with a circumference, the product between the segment external to the circumference and the total segment in one of the secant lines is equal to the product of the corresponding segments in the other secant line.

This means that

$(5+4)*4 = (x+3)*3$

Now we solve the equation for the variable x

$(9)*4 = (x+3)*3$

$36 = 3x + 9$

$36-9 = 3x$

$3x =27$

$x =9$

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a box contains 20 red, 10 blue and 30 yellow beads. what is the probability of a bead drawn at random being yellow or blue?

dexar [7]

Answer:

2/3

Step-by-step explanation:

1. add all the beads up together:

20+10+30= 60

2. add the blue and yellow beads up:

10+30= 40

3. put 40 over 60

40/60 which equals 2/3

4. the final answer:

2/3

5 0

3 years ago

A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute

Katyanochek1 [597]

Answer:

Step-by-step explanation:

Given that:

sample size n = 36

standard deviation = 10.1

level of significance ∝ = 0.10

The null hypothesis and the alternative hypothesis can be computed as follows:

$H_0 : \sigma = 10$

$H_1 : \sigma \neq 10$

The test statistics can be computed as follows:

$X^2 = \dfrac{(n -1)s^2 }{\sigma ^2}$

$X^2 = \dfrac{(36 -1)10.1^2 }{10^2}$

$X^2 = \dfrac{(35)102.01 }{100}$

$X^2 = \dfrac{3570.35 }{100}$

$X^2 =35.704$

degree of freedom = n - 1 = 36 - 1 = 35

Since this test is two tailed .

The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)

P - value = 2 × 0.435163515

P - value = 0.8703 ( to four decimal places)

Decision Rule : To reject the null hypothesis if P - value is less than the 0.10

Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.