Question

1. If one letter is chosen at random from the word combed, what is the probability that the letter chosen will be a "d"?

Answer 1

Answer:

• Probability that the chosen letter is d is $\frac{1}{6}$

• Probability of rolling a 7 is $\frac{1}{6}$
• Probability of picking a green is $\frac{5}{21}$

Step-by-step explanation:

• Probability of choosing d in the word "combed"

Given:

Alphabet: d

Word: combed

First, we note down the length of the word "combed";

The length is 6 characters

The we check the number of occurrence of d in the word "combed"

Occurrence of d = 1

Probability is then calculated as;

Probability of choosing d = $\frac{Number of Occurrence}{Total Observation}$

By Substitution; Probability = $\frac{1}{6}$

• Probability of rolling a 7 in a cube of side numbers 2,4,8,9,4, and 7

Given:

Roll number = 7

Sample Space= {2,4,8,9,4, 7}

Sample Size, n(S) = 6

We check the number of occurrence of 7 in the sample space

Number of occurrence = 1

Probability is then calculated as;

Probability of rolling a 7 = $\frac{Number of Occurrence}{Sample Size}$

By Substitution; Probability = $\frac{1}{6}$

• Probability of pulling out a green marble

Given

Red = 12

Green = 10

Yellow = 2

Blue = 19

Purple = 9

Total = 12 + 10 + 2 + 19 + 9 = 42

Probability of picking a green marble is then calculated as;

Probability of choosing d = $\frac{Number of Green}{Total}$

By Substitution; Probability = $\frac{10}{42}$

Probability = $\frac{5}{21}$

Answer 2

1.) 1/6 Chance the letter will be D due to having 1 letter D out of 6 total leters
2.) 1/6 Chance of rolling a 7 due to having 6 total numbers and only one 7
3.) 10/52 Chance of pulling green due to only having 10 green marbles and 52 total marbles