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3 years ago

8

Need asapif x=12 what is the value of p in this equation? p=

6%7D%20-4" id="TexFormula1" title="\frac{x^{2} }{6} -4" alt="\frac{x^{2} }{6} -4" align="absmiddle" class="latex-formula">

1 answer:

yarga [219]3 years ago

5 0

The answer to the equation is 65

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For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l

murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

$X_i \sim \frac{G_1}{2}$

$E(X_i)=2 \\$

$Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\$

$= \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2$

Now we calculate the $\bar X \sim N(2, \sqrt{\frac{2}{n}})\\$

$\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}} \sim N(0, 1)\\$

$\to \sum^n_{i=1} \frac{X_i - 2}{n} \times\sqrt{\frac{n}{2}}} \sim N(0, 1)\\\\\to \sum^n_{i=1} \frac{X_i - 2}{\sqrt{2n}} \sim N(0, 1)\\$

$\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\$

$\to P(-1 \leq X_n \leq 2) = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\$

$= 0.92 -0.24\\\\= 0.68$

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kherson [118]

Answer:

The answer is D. 110

Step-by-step explanation:

You add 8 and 3 and get 11 first because in parentheses, and then you subtract that by 14, which will give you 3. Then you multiply 3 times 5 to get 15 and add that to 95 to get your answer. Hope this helps!

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52 or 51 kids on each bus.

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<span>Percent error is the percentage ratio of the observed value and the true value difference over the true value so you don't need plus or minus signs. Thanks!</span>

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2 years ago

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Paul [167]

Answer:

bruh there isnt a graph or anything we cant answer it

Step-by-step explanation:

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