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Sedaia [141]
3 years ago
11

2x^3 + x^2 – 7x – 6 divided by 2x +3

Mathematics
1 answer:
nevsk [136]3 years ago
6 0

Answer:

x^2 -x -2

Step-by-step explanation:

Use polynomial long division.

           0 + x^2  -x  -2

           ___________________________________

(2x+3)  |  2x^3  +x^2  -7x  -6

           -2x^3  -3x^2

            _________

                      -2x^2 -7x

                      +2x^2  +3x

                       __________

                                   -4x  -6

                                    +2x  +6

                                   _______

                                          0

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Answer:

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Step-by-step explanation:

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2 years ago
If a parallelogram has diagonals that are perpendicular bisectors of each other, what is the most descriptive name for it?
Feliz [49]
Both a rhombus and a rectangle have diagonals that are perpendicular bisectors, but the ones formed in a square are all congruent, so that is probably the most descriptive one.
6 0
3 years ago
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3 years ago
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
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balandron [24]

Answer:

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Step-by-step explanation:

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Hope this helps! Have an Awesome day!! :-)

5 0
3 years ago
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