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Rasek [7]
3 years ago
11

There are (10^8)^2 ⋅ 10^0 candies in a store. What is the total number of candies in the store?

Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0
The answer would be the 3rd one, 10 to the power of 16 (10^16).

This is because you multiply the 2 powers (2 and 8) to get 16. When there is one power within a set of parenthesis and one power on the outside the parenthesis. Since there is a 10 to the 0 power (10^0) you add this power to 16 since it is multiplying integers with exponents. Thus getting 10^16 as an answer.

I hope this helps!
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Solve for x: −2(x + 3) = −2(x + 1) − 4. (1 point)
NeTakaya

Answer:

Hey there!

Let's solve our equation below.

-2(x+3)= -2(x+1)-4

Let's distribute the parentheses.

-2x-6=-2x-2-4

We combine like terms.

-2x-6=-2x-6

We add 6 to both sides.

-2x=-2x

We divide both sides by -2

x=x

If, when solving an equation, you get one number or variable that equals itself, there are infinitely many solutions.

We can plug anything into this equation and it will always equal to same things, since x is just equal to whatever x value you want.

Therefore, there are infinitely many solutions.

I hope this helps!

8 0
3 years ago
PLEASE HELP I WILL MARK YOU AS BRAINLIEST!
solong [7]

Answer:

12 units²

Step-by-step explanation:

Area = ½ × base × height

= ½ × 4 × 6

= 12 units²

8 0
2 years ago
Evaluate.<br> (-4)=<br> (-7) = 0<br> Please help ASAP!!
denis-greek [22]
  • Answer:

<em>(-4)³ = (-4)(-4)(-4) = 16(-4) = - 64</em>

<em>(-7)² = (-7)(-7) = 49</em>

<em>(-)×(-) = +</em>

<em>(-)×(+) = -</em>

4 0
3 years ago
Can someone answer these questions ? thank you
Naya [18.7K]

Answer:

Step-by-step explanation:

12a)To rationalize the denominator, multiply the denominator and numerator by √5.

\frac{15}{\sqrt{5}}=\frac{15*\sqrt{5}}{\sqrt{5}*\sqrt{5}}\\\\=\frac{15\sqrt{5}}{5}\\\\=3\sqrt{5}

b) (a+b)² = a² + 2ab + b²

(1 +√3)² = 1² + 2*1*√3 + (√3)²

= 1 + 2√3 + 3

= 4 + 2√3

a = 4 ; b =2

13) (a + b)(a - b) = a² - b²

\frac{(6-\sqrt{5})(6+\sqrt{5})}{\sqrt{31}}=\frac{6^{2}-(\sqrt{5})^{2}}{\sqrt{31}}\\\\ =\frac{36-5}{\sqrt{31}}\\\\=\frac{31}{\sqrt{31}}\\\\=\frac{31*\sqrt{31}}{\sqrt{31}*\sqrt{31}}\\\\=\frac{31\sqrt{31}}{31}\\\\=\sqrt{31}

5 0
3 years ago
I don't understand how to do this. Can someone help?
miskamm [114]
Time used for the call to Zurich: ($5-$1.25)/$0.25=15 minutes
15minutes+3minutes=18minutes
Time used for the call to London: ($7.25-$1.25)/$0.25=24 minutes
24minutes+3minutes=27minutes
Difference between the two calls:27-18=9minutes
3 0
3 years ago
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