All categories

3 years ago

There are (10^8)^2 ⋅ 10^0 candies in a store. What is the total number of candies in the store?

1 answer:

6 0

The answer would be the 3rd one, 10 to the power of 16 (10^16).

This is because you multiply the 2 powers (2 and 8) to get 16. When there is one power within a set of parenthesis and one power on the outside the parenthesis. Since there is a 10 to the 0 power (10^0) you add this power to 16 since it is multiplying integers with exponents. Thus getting 10^16 as an answer.

I hope this helps!

You might be interested in

Suppose each cube in this right rectangular prism is a 1 2 -inch unit cube. What are the dimensions of the prism? What is the vo

lubasha [3.4K]

Answer:

<h2>The lengths of the sides of a small cube are = foot. Volume of cube = side x side x side. V = = cubic foot. Number of small cubes that can be packed in the prism = = = = 180 cubes. Hence, 180 cubes can be packed into rectangular prism. Part B: Unit cube volume is 1x1x1 =1 cubic foot. So, 180 cubes will have 180 cubic foot volume.</h2>

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Which of the following represents the formula that could be used to find the height of the cone

podryga [215]

If you know the volume then:
(3 * Cone Volume) / (PI * radius^2) = height

3 0

3 years ago

Find the sum of a finite geometric sequence from n = 1 to n = 6, using the expression −2(5)n − 1.

vazorg [7]

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=-2\\
r=5\\
n=6
\end{cases}
\\\\\\
S_6=-2\left( \cfrac{1-5^6}{1-5} \right)$

8 0

2 years ago

Read 2 more answers

A toy store’s percent markup is 50%. The wholesale price of a model train is $77. Find the retail price.

Radda [10]

It's original price was $38.50

5 0

3 years ago

Read 2 more answers

Find the roots of:

Elena-2011 [213]

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \ 2x^3-7x^2+8x-3=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

| 2 -7 8 -3

1 | 2 -5 3

| 2 -5 3 0

1 | 2 -3

2 -3 0

So the factorization is (x-1)² (2x-3)=0. So:

$\bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2} }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \ x^3-x^2-4=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

| 1 -1 0 -4

2 | 2 2

1 2 2 0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

$\bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \ 6x^3+7x^2-9x+2=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

| 6 7 9 2

-2 | -12 10 -2

6 -5 1 0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

$\bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}$

$\large\displaystyle\text{$\begin{gathered}\sf \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}$

6 0

2 years ago