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3 years ago

There are (10^8)^2 ⋅ 10^0 candies in a store. What is the total number of candies in the store?

1 answer:

6 0

The answer would be the 3rd one, 10 to the power of 16 (10^16).

This is because you multiply the 2 powers (2 and 8) to get 16. When there is one power within a set of parenthesis and one power on the outside the parenthesis. Since there is a 10 to the 0 power (10^0) you add this power to 16 since it is multiplying integers with exponents. Thus getting 10^16 as an answer.

I hope this helps!

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Whats the least common denominator of 9, 13, and 20

aliya0001 [1]

Answer:

13 = 13

20 = 2^2 • 5

9 = 32

Prime Factor Number 13 Number 20 Number 9 L.C.M

2 0 2 0 2

3 0 0 2 2

5 0 1 0 1

13 1 0 0 1

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2 years ago

A secret code consists of 3 digits, followed by 2 letters, followed by 1 of the following symbols: @

WINSTONCH [101]

The answer is B hope this helps

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3 years ago

Which is the graph of f (x) = f (one-half) Superscript x? On a coordinate plane, an exponential decay function decreases from qu

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Answer:

answer is B. :)

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2 years ago

Read 2 more answers

The revenue, in dollars, of a company that produces jeans can be modeled by 2x2 + 17x – 175. The cost, in dollars, of producing

topjm [15]

The profit that is gained from the production and selling of the jeans is given to be calculated through the the equation,
P = 20x - 50
For 75 jeans, we just have to substitute 75 to the x's of the equation. This then becomes,
P = 20(75) - 50 = 1450
Thus, the company will make a profit of $1450 by production of 75 jeans.

8 0

3 years ago

Read 2 more answers

A red die and a blue die are rolled. You win or lose money depending on the sum of the values of the two dice. If the sum is 6 o

olganol [36]

Answer:

The expected value of X is $0.0833.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

For each dice, there are 6 possible outcomes(values from 1 to 6). So for 2 dices, there are $6^2 = 36$ desired outcomes.

Desired outcomes:

Sum 5: (1,4), (2,3), (3,2), (4,1).

Sum 6: (1,5),(2,4),(3,3),(4,2),(5,1)

Sum of 9: (3,6), (4,5), (5,4), (6,3)

Sum of 10: (4,6), (5,5), (6,4)

Sum of 12: (6,6)

Probabilities:

5 + 3 = 8 outcomes in which the sum is 6 or 10, that is, 8/36 probability of winning $4.

4 + 4 + 1 = 9 outcomes in which the 5, 9, or 12, that is, 9/36 probability of winning $1.

36 - (8 + 9) = 36 - 17 = 19 remaining outcomes, that is, 19/36 probability of losing $2.

What is the expected value of X?

Multiplication of each outcome by its probability. So

$E(X) = \frac{8}{36}*4 + \frac{9}{36}*1 - \frac{19}{36}*2 = \frac{8*4 + 9*1 - 19*2}{36} = \frac{32 + 9 - 38}{36} = \frac{3}{36} = 0.0833$

The expected value of X is $0.0833.

4 0

3 years ago