If the pond were a rectangle, then:
length=15 m
width=6 m
We would have to calculate the perimeter of this rectangle.
Perimeter of a rectangle=2(length)+2(width)
Perimeter of this rectangle=2(15 m)+2(6 m)=30 m+12 m=42 m
We need 42 m and I only have 40 m, therefore, it would not be enough for fencing the pond.
Step-by-step explanation:
By Cosine rule, we have
s² = t² + u² - 2(t)(u)(cosS)
=> cosS = (t² + u² - s²)/2tu
=> cosS = (58² + 27² - 50²) / (2 * 58 * 27) = 0.5086.
Therefore S = cos^-1(0.5086) = 59.4° (1d.p.)
I'm not really sure what the question is here, because you just gave a statement... but if you are trying to get an expression from words, here is what it would be:
A = 10N
I'm also not sure if "a number" is equal to the same as "a number" at the end, but I'm guessing not. If it is though, and you're trying to find the value of A, the answer would be:
A = 10
<em>*</em><em>Please provide the question you are asking here, not just statements, next time, so that people can help you.</em>
<em />
I hope this helped :)
Multiplying fractions is simple. You just multiply across so 7/3 x 2/3 is 14/9 and that is the simplest form.
Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56
fts
Now using Formula for time and range as
Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,
T is approximately equals to 4 sec.
