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kvv77 [185]
4 years ago
8

Based only on the given information,it is guaranteed that ad=db

Mathematics
2 answers:
TiliK225 [7]4 years ago
8 0
Please give picture so i can help
babymother [125]4 years ago
7 0
What's the rest of the question?
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How can you find the area of a shape with fractional or decimal side lengths?
SOVA2 [1]

Answer:

You convert the fractions to a decimal, nut the rest is still the same

Step-by-step explanation:

3 0
3 years ago
What are the solutions to the following system of equations? y = x2 + 3x − 7 3x − y = −2 (2 points) (3, 11) and (−3, −7) (11, 3)
Minchanka [31]
ANSWER

(3, 11) and (−3, −7)


EXPLANATION

The given system of equations are:


y =  {x}^{2}  + 3x - 7

and

3x - y =  - 2

or

y = 3x  + 2


We equate the two equations to obtain,



{x}^{2}  + 3x - 7 = 3x + 2

We rewrite in standard quadratic form to obtain,

{x}^{2}  + 3x  - 3x - 7 - 2 = 0


This simplifies to

{x}^{2}- 9= 0


We solve for x to obtain,


{x}^{2}  = 9

x =  \pm \sqrt{9}

x =  \pm 3

x = 3 \: or \: x =  - 3

When
x = 3

y = 3(3) + 2 = 11

When x=-3,

y = 3(  - 3) + 2 =  - 7


Therefore the solution for the system is (3, 11) and (−3, −7).
7 0
3 years ago
Read 2 more answers
Does someone know where on the quadrant go on the coordinate planes ​
stiv31 [10]

The origin is at 0 on the x-axis and 0 on the y-axis. The intersecting x- and y-axes divide the coordinate plane into four sections. These four sections are called quadrants. Quadrants are named using the Roman numerals I, II, III, and IV beginning with the top right quadrant and moving counter clockwise.

6 0
4 years ago
1 What is the RANGE for the following graph?<br><br> PLEASE HELP 25 POINTS
xenn [34]
I cant see the picture
5 0
3 years ago
Write the equation of the line in fully simplified slope-intercept form.
Lina20 [59]

Answer:

y=-6x+2

Step-by-step explanation:

Hi there!

Slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when x=0)

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

m=\displaystyle \frac{y_2-y_1}{x_2-x_1} where two points that fall on the line are (x_1,y_1) and (x_2,y_2)

Given the graph, we determine which points we could use. For example, we could use the two points (0,2) and (1,-4):

m=\displaystyle \frac{-4-2}{1-0}\\\\m=\displaystyle \frac{-6}{1}\\\\m=-6

Therefore, the slope of the line is -6. Plug this into y=mx+b:

y=-6x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

Recall that the y-intercept occurs when x=0. Given the point (0,2), we know that the y-intercept is 2. Plug this into y=-6x+b:

y=-6x+2

I hope this helps!

5 0
3 years ago
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