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BaLLatris [955]

4 years ago

12

Which expression is equal to sec x° multiplied by cot x°?

1 answer:

IceJOKER [234]4 years ago

3 0

Secant function is the inverse of cosine function while cotangent is the inverse of tangent function equal to cosine over sine. when we multiply both inverse functions, the result is cos2 x over sin x. cos2 x is equal to 1 - sin2 x. the simplified form is csc x - sin x

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If anyone can help with either one that’d be great

Volgvan

4. Solve

$1430 = 0.55t^2 + 550$

$1430 - 550 =880 = 0.55t^2$

$880/0.55 = 1600 = t^2$

$t= \pm \sqrt{1600} = \pm 40$

On the positive answer makes sense.

Answer: Month 40

5. The throw ends when the height is zero (I guess we're ignoring rolling).

$0 = -0.02x^2 + x + 6$

$x = \dfrac{-1 \pm \sqrt{1^2 - 4(6)(-0.02)}}{2(-0.02)}$

Only the negative sign for the plus/minus will give a sensible, positive answer:

$x = \dfrac{-1 - \sqrt{1^2 - 4(6)(-0.02)}}{2(-0.02)} = 55.4138$

Answer: 55.4 feet

6 0

4 years ago

Reggie bought a pair of hiking boots that were discounted by 30% off the original price. If the original price was $66.00, what

Free_Kalibri [48]

Answer:

$46.20

Step-by-step explanation:

We can create a proportion to find the sale on the original price. A proportion is an equation where two ratios are set equal to each other. We create two fractions using the prices and percents. If the price is discounted by 30% then we pay 70% of the price.

$\frac{70}{100} =\frac{x}{66}$

We begin solving by cross multiplying numerator to denominator of each fraction.

$70(66)=100(x)\\4620=100x\\\frac{4620}{100}=\frac{100x}{100} \\46.20=x$

4 0

4 years ago

What is the prime factorization of 48?<br> A)4*12<br> B) 24×3<br> C)23x32<br> D)236

gtnhenbr [62]

Answer:

So, the prime factors of 48 are 2 × 2 × 2 × 2 × 3 or we can also write them as 2^4 × 3.

Step-by-step explanation:

I just googled it. So B. I think.

3 0

3 years ago

Can someone know this help me out asap

Ksivusya [100]

Answer:

The Growth rate would be 1x and 16y

Step-by-step explanation:

BECAUSE IT SAYS THE ORDER IN THE FIRST PART OF THE GRAPH(oops caps lock)

7 0

3 years ago

A plane flying horizontally at an altitude of 1 mi and a speed of 470 mi/h passes directly over a radar station. Find the rate a

kiruha [24]

Answer:

407 mi/h

Step-by-step explanation:

Given:

Speed of plane (s) = 470 mi/h

Height of plane above radar station (h) = 1 mi

Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.

Consider a right angled triangle representing the above scenario.

We can see that, the height 'h' remains fixed as the plane is flying horizontally.

Speed of the plane is nothing but the rate of change of horizontal distance of plane. So, $s=\frac{dx}{dt}=470\ mi/h$

Now, applying Pythagoras theorem to the triangle, we have:

$D^2=h^2+x^2\\\\D^2=1+x^2$

Differentiating with respect to time 't', we get:

$2D\frac{dD}{dt}=0+2x\frac{dx}{dt}\\\\\frac{dD}{dt}=\frac{x}{D}(s)$

Now, when the plane is 2 miles away from radar station, then D = 2 mi

Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,

$2^2=1+x^2\\\\x^2=4-1\\\\x=\sqrt3=1.732\ mi$

Now, plug in all the given values and solve for $\frac{dD}{dt}$ . This gives,

$\frac{dD}{dt}=\frac{1.732\times 470}{2}=407.02\approx 407\ mi/h$

Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.

6 0

3 years ago