Answer:
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes
Step-by-step explanation:
We have the standard deviation for the sample, but not for the population, so we use the students t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 35 - 1 = 35
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of ![1 - \frac{1 - 0.9}{2} = 0.975([tex]t_{975}](https://tex.z-dn.net/?f=1%20-%20%5Cfrac%7B1%20-%200.9%7D%7B2%7D%20%3D%200.975%28%5Btex%5Dt_%7B975%7D)
). So we have T = 2.0322
The margin of error is:
M = T*s = 2.0322*30 = 60.97
The upper end of the interval is the sample mean added to M. So it is 204 + 60.97 = 264.97
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes
Answer: 
<u>Step-by-step explanation:</u>
To find the tangent, you need to find the derivative with respect to x.
Then substitute x = 1 into the derivative.
Given: 0 = 2x² - xy - y²
Derivative: 0 = 4x - y' - 2yy'
Solve for y': 2yy' + y' = 4x
y'(2y + 1) = 4x
If the p-value is smaller than the level of significance, then it indicates strong evidence against the null hypothesis, as there is less than a 5% probability the null hypothesis is correct.
In this question,
A p-value is a probability, calculated after running a statistical test on data and it lies between 0 and 1. The p-value only tells you how likely the data you have observed is occurred under the null hypothesis.
One of the most commonly used p-value is 0.05. If the value is greater than 0.05, the null hypothesis is considered to be true. If the calculated p-value turns out to be less than 0.05, the null hypothesis is considered to be false, or nullified (hence the name null hypothesis).
A small p-value (< 0.05 in general) means that the observed results are unusual, assuming that they were due to chance only. Now, the smaller the p-value, the stronger the evidence that should reject the null hypothesis.
Hence we can conclude that if the p-value is smaller than the level of significance, then it indicates strong evidence against the null hypothesis, as there is less than a 5% probability the null hypothesis is correct.
Learn more about p-value here
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Answer:what is the question
Step-by-step explanation:
Simplify \frac{5}{3}x35x to \frac{5x}{3}35x
x-\frac{5x}{3}<3x−35x<3
2
Simplify x-\frac{5x}{3}x−35x to -\frac{2x}{3}−32x
-\frac{2x}{3}<3−32x<3
3
Multiply both sides by 33
-2x<3\times 3−2x<3×3
4
Simplify 3\times 33×3 to 99
-2x<9−2x<9
5
Divide both sides by -2−2
x>-\frac{9}{2}x>−29
