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wlad13 [49]
3 years ago
12

Sam has $2,450 in his bank account. He spends $20 each week on gas money. After how many weeks will sams account balance fall be

low $1000 in inequality form?
Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

  • 2450 -20w < 1000
  • 73 weeks

Step-by-step explanation:

The balance (b) in Sam's account will be the initial balance less 20 times the number of weeks (w) that he withdraws gas money.

  b = 2450 -20w

We want the inequality to express the condition that this balance is below 1000:

  b < 1000

  2450 -20w < 1000 . . . . . substitute for b

__

The solution to this can be found by subtracting 2450, then dividing by -20.

  -20w < -1450

  w > 72.5

If weeks are counted in whole numbers, Sam's balance will be below $1000 after 73 weeks.

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Answer:

Amount in 4% account: $550

Step-by-step explanation:

Use simple interest formula I=P\cdot r\cdot t, where

I = interest

P = principal

r = rate (as decimal)

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<u>5% account:</u>

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I_2=(1,500-x)\cdot 0.05\cdot 1=0.05(1,500-x)

You have earned $69.50 in total, so

I_1+I_2=69.50\\ \\0.04x+0.05(1,500-x)=69.50\\ \\4x+5(1,500-x)=6,950\\ \\4x+7,500-5x=6,950\\ \\4x-5x=6,950-7,500\\ \\-x=-550\\ \\x=550\\ \\1,500-x=1,500-550=950

Amount in 4% account: $550

Amount in 5% account: $950

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