1.
Perpendicular. y=3x+4
Parallel. y=-1/3 x-8/3
2.
Perpendicular. y=-x-1
Parallel. y=x+11
3.
Perpendicular. y=7/4 x+8
Parallel. y=-7/4 x-9/7
4.
Perpendicular. y=4/5 x-3
Parallel. y=-5/4 x+35/2
yeesh, that took a while :) hope I helped!
the answer would be: x= -24
Answer:
28/9
Step-by-step explanation:
We will have to convert the given question into improper fraction before solving
So let's solve the question
3 1/9
Can be written as 28/9 which is improper fraction
Since there's nothing that can be used to divide both the numerator and denominator
Then our final answer is 28/9
But in the case where the fraction can be divided we can actually solve further
Answer:
cos(θ) = 3/5
Step-by-step explanation:
We can think of this situation as a triangle rectangle (you can see it in the image below).
Here, we have a triangle rectangle with an angle θ, such that the adjacent cathetus to θ is 3 units long, and the cathetus opposite to θ is 4 units long.
Here we want to find cos(θ).
You should remember:
cos(θ) = (adjacent cathetus)/(hypotenuse)
We already know that the adjacent cathetus is equal to 3.
And for the hypotenuse, we can use the Pythagorean's theorem, which says that the sum of the squares of the cathetus is equal to the square of the hypotenuse, this is:
3^2 + 4^2 = H^2
We can solve this for H, to get:
H = √( 3^2 + 4^2) = √(9 + 16) = √25 = 5
The hypotenuse is 5 units long.
Then we have:
cos(θ) = (adjacent cathetus)/(hypotenuse)
cos(θ) = 3/5
Answer:
The first incorrect justification is in step 2.
Step-by-step explanation:
<u>Step 2</u>. BC2 = AC • DC
2. BC ÷ DC = BC ÷ AC because triangle ABC is similar to triangle BDC
It's supposed to be AC ÷ BC not BC ÷ AC.