Its C.
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The definition of similar triangles says that 2 triangles are similar if they have the same shape but different size. There are two criteria to check for this:
1) If all angles in one triangle are equal to the angles in another one, then the 2 are equal.
2) If the sides have the same proportions, then the 2 triangles are similar.
1) We have that all the angles of the 2 triangles have an equal angle in the other triangle. In specific, Q is matched to B, P to A and R to C. Hence, since corresponding angles are congruent, the two triangles are similar.
2) Here we are given information about the sides of the triangles, so we will check the second criterion. We form the ratio of the largest sides of each trangle and the shortest sides. 30/5=6. For the shortest sides, 18/3=6. Finally for the middle sides, 24/4=6. Hence, we have that the triangles are similar since the ratios are equal. (it doesn't matter whether we take the bigger or the smaller side as a numerator, as long as we are consistent).
Answer:
Let the scores on the first two test be x
Let score for third test be 14 exceeds second( or first) = x + 14
Total = 233
x + x + (x + 14) = 233
3x + 14 = 233
3x = 219
x = 73
Score of the third test = x + 14 = 73 + 14 = 87
Therefore, the scores are 73, 73, 87
Let's do both. For the first one, we can add 1 to both sides using the property of equality, and get 4x < -12. Then, we divide by 4, getting us x<-3. For the second, we subtract 3 from both sides to get -2x < 4. Then, we divide by -2 on both sides, but when we divide by a negative we have to switch the sign. So, we get x > -2. Hope this helps.
