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3 years ago

The sum of two consecutive integers is at most 223. What is the larger of the two integers?

Mathematics

2 answers:

irinina [24]3 years ago

8 0

Answer:

112

Step-by-step explanation:

Vlada [557]3 years ago

6 0

Divide 223 by 2: 223/2 = 111.5

Then fix one number to 111.5 - 0.5 ann the other to 111.5 + 0.5

The two numbers are 111 and 112.

Then the answer is 112.

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konstantin123 [22]

Answer:

Step-by-step explanation:

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3 years ago

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2 years ago

Help me find area please asap

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3 years ago

Can i please get help with this question?

Aleonysh [2.5K]

1,5 . n = 13,65

We know:

$1,5=\frac{15}{10}$

and

$13,65=\frac{1365}{100}$

So,

$\frac{15}{10}.n=\frac{1365}{100}$

Pass $\frac{15}{10}$ as division.

$n = \frac{\frac{1365}{100}}{\frac{15}{10}}$

Btw, we also know:

$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a.d}{b.c}$

So,

$n = \frac{\frac{1365}{100}}{\frac{15}{10}}$

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$n = \frac{13650}{1500}$

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3 years ago

How to you put 5abc+2a^2+6abc i standard form step by step??

user100 [1]

$5abc+2a^2+6abc$

$(5abc+6abc)+2a^2$ $| Gather \ like \ terms|$

$11abc+2a^2
 
$

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3 years ago