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djyliett [7]
3 years ago
13

The sum of two consecutive integers is at most 223. What is the larger of the two integers?

Mathematics
2 answers:
irinina [24]3 years ago
8 0

Answer:

112

Step-by-step explanation:

Vlada [557]3 years ago
6 0
Divide 223 by 2: 223/2 = 111.5

Then fix one number to 111.5 - 0.5 ann the other to 111.5 + 0.5

The two numbers are 111 and 112.

Then the answer is 112. 
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If a circle is 9 pi cm what is the radius of the circle
olganol [36]

Answer:

<h2>          4.5 cm</h2>

Step-by-step explanation:

L = 2×π×r

9π cm = 2πr

9 cm = 2r

r = 4.5 cm

5 0
3 years ago
Find the image (0,0) after two reflections first across y=3 and then across x-axis
Alina [70]
Refrection of point (0, 0) across y = 3 gives point (0, 6)
Refrection of point (0, -6) across the x-axis gives point (0, -6)
3 0
3 years ago
Read 2 more answers
Bobby hopes that he will someday be more than 70 inches tall. he is currently 61 inches tall. how many more inches,
Dominik [7]
Bobby should grow an amount greater than 70-61 = 9 inches to become taller than 70 inches. Therefore, the correct answer is that Bobby must grow an amount of x> 9 inches to be taller than 70 inches.
4 0
3 years ago
The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi
Elan Coil [88]

Answer:

7-3.182 \frac{13.638}{\sqrt{4}}= -14.698

7+3.182 \frac{13.638}{\sqrt{4}}= 28.698

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150  

Weight after diet 170 130 215 152

We define the random variable D = before-after and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

And the deviation with:

s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

And after replace we got:

\bar D= 7, s_d = 13.638

And the confidence interval for this case would be given by:

\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1= 4-1=3

For the 95% of confidence the value for the significance is \alpha=0.05 and the critical value would be t_{\alpha/2}= 3.182. And replacing we got:

7-3.182 \frac{13.638}{\sqrt{4}}= -14.698

7+3.182 \frac{13.638}{\sqrt{4}}= 28.698

6 0
3 years ago
PLEASE HELP!!
nasty-shy [4]
-5x+2y=6
2y=6+5x
y=5/2x + 6

x+3y=3
3y=3-x
y=-x/3+1

-2x+y=4
y=2x+4

4x+9y=-9
9y=-4x-9
y=-4/9x+1

Hope this helps.
6 0
3 years ago
Read 2 more answers
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