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3 years ago

The sum of two consecutive integers is at most 223. What is the larger of the two integers?

Mathematics

2 answers:

irinina [24]3 years ago

8 0

Answer:

112

Step-by-step explanation:

Vlada [557]3 years ago

6 0

Divide 223 by 2: 223/2 = 111.5

Then fix one number to 111.5 - 0.5 ann the other to 111.5 + 0.5

The two numbers are 111 and 112.

Then the answer is 112.

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pantera1 [17]

ANSWER

C. 2.402

EXPLANATION

Given that:

$log_{3}(2) = 0.631$

$log_{3}(7) = 1.771$

We want to evaluate:

$log_{3}(14) = log_{3}(2 \times 7)$

Use the product rule of logarithms.

$log_{a}(mn) = log_{a}(m) + log_{a}(n)$

$log_{3}(14) = log_{3}(2) + log_{3}(7)$

$log_{3}(14) = 0.631 + 1.771$

$log_{3}(14) = 2.402$

The third choice is correct.

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